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3 years ago

What is the mass prevent of manganese (mn) in potassium permanganate (KMnO4)

Chemistry

1 answer:

oksian1 [2.3K]3 years ago

4 0

Answer:

Mass percent of Mn is 34.76 %

Explanation:

<em>Mass percent</em> of an element is the mass of that element divided by the total mass of the elements forming that compound (or molecular mass.

So,

Mass percent of Mn will be given as,

%Mn = Atomic Mass of Mn / Molecular Mass of KMnO₄ × 100

So,

Atomic Mass of Mn = 54.94 g/mol

Molecular Mass of KMnO4 = 158.034 g/mol

Putting values in above formula,

%Mn = 54.94 g/mol ÷ 158.034 g/mol × 100

%Mn = 34.76 %

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3 years ago

Calculate the equilibrium constant for the reaction using the balanced chemical equation and the concentrations of the substance

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3 years ago

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topjm [15]

Answer:

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4 0

3 years ago

What is the mass prevent of manganese (mn) in potassium permanganate (KMnO4)​

What is the mass prevent of manganese (mn) in potassium permanganate (KMnO4)