Question

What is the mass prevent of manganese (mn) in potassium permanganate (KMnO4)​

Answer 1

Answer:

               Mass percent of Mn is 34.76 %

Explanation:

                    Mass percent of an element is the mass of that element divided by the total mass of the elements forming that compound (or molecular mass.

So,

Mass percent of Mn will be given as,

          %Mn  =  Atomic Mass of Mn / Molecular Mass of KMnO₄ × 100

So,

Atomic Mass of Mn  =  54.94 g/mol

Molecular Mass of KMnO4  =  158.034 g/mol

Putting values in above formula,

          %Mn  =  54.94 g/mol ÷ 158.034 g/mol × 100

          %Mn  = 34.76 %