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zzz [600]
3 years ago
6

What is the mass prevent of manganese (mn) in potassium permanganate (KMnO4)​

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

               Mass percent of Mn is 34.76 %

Explanation:

                    <em>Mass percent</em> of an element is the mass of that element divided by the total mass of the elements forming that compound (or molecular mass.

So,

Mass percent of Mn will be given as,

          %Mn  =  Atomic Mass of Mn / Molecular Mass of KMnO₄ × 100

So,

Atomic Mass of Mn  =  54.94 g/mol

Molecular Mass of KMnO4  =  158.034 g/mol

Putting values in above formula,

          %Mn  =  54.94 g/mol ÷ 158.034 g/mol × 100

          %Mn  = 34.76 %

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