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alexandr1967 [171]
2 years ago
10

Element X has two isotopes. One has a mass of 45.0 amu and is 45.0% abundant. The other has a mass of 47.0 amu and is 55.0% abun

dant. What is the average atomic mass of element X?*
0 46.1 amu
O 36.5 amu
0 43.8 amu
0 48.9 amu
Chemistry
1 answer:
vovikov84 [41]2 years ago
7 0

The <em>average</em><em> </em>atomic mass of element X that has two isotopes (one of 45.0 amu mass and 45% abundance and the other of 47.0 amu mass and 55.0% abundance) is 46.1 amu (option 1).  

The <em>average </em>atomic mass (A) of element X can be calculated as follows:

A = m_{1}\%_{1} + m_{1}\%_{1}    (1)

Where:

m₁: is the mass of isotope 1 = 45.0 amu

m₂: is the <em>mass </em>of <em>isotope </em>2 = 47.0 amu

%₁: is the abundance percent of <em>isotope </em>1 = 45.0 %

%₂: is the <em>abundance percent</em> of <em>isotope </em>1 = 55.0 %

Hence, the <u>average atomic mass</u> is (eq 1):

A = m_{1}\%_{1} + m_{1}\%_{1} = 45.0 amu*45.0\% + 47.0 amu*55.0\% = 45.0 amu*0.45 + 47.0 amu*0.55 = 46.1 amu  

Therefore, the <em>average </em>atomic mass of element X is 46.1 amu (option 1).

Find more about atomic mass here:

  • brainly.com/question/3187640?referrer=searchResults
  • brainly.com/question/17338557?referrer=searchResults

I hope it helps you!

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Given,

Moles of metal M = 0.300 moles

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1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂

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