Answer:
19.12 m/s.
Explanation:
The following data were obtained from the question:
Final velocity (v) = 0 m/s
Breaking Acceleration (a) = – 4.57 m/s²
Distance (s) = 40 m
Initial velocity (u) =.?
The initial velocity of the car can be obtained as illustrated below:
v² = u² + 2as
0² = u² + (2 × –4.57 × 40)
0 = u² + (– 365.6)
0 = u² – 365.6
Collect like terms
u² = 0 + 365.6
u² = 365.6
Take the square root of both side
u = √365.6
u = 19.12 m/s
Therefore, the car was initially moving at 19.12 m/s.
When a body performs a uniform circular motion, the direction of the velocity vector changes at every moment. This variation is experienced by the linear vector, due to a force called centripetal, directed towards the center of the circle that gives rise to centripetal acceleration, the mathematical expression is given as,
Where,
v = Tangential Velocity
r = Radius
The linear velocity was 2010m/s in a radius of 0.159m, then the centripetal acceleration is
Therefore the centripetal acceleration of the end of the rod is
John Brown - The abolitionist who led the raid on Harper's Ferry.
John C. Fremont - Led the United States Troops into California.
Harriet Tubman - Underground Railroad.
Santa Anna - led the Mexican Army against the Alamo and the Texas forces.
Jim Bowie - was one of the Texans that died at the Alamo.
William Lloyd Garrison - published "The Liberator."
Tariff of Abomination - Tariff of 1828.
Answer:
The correct answer is H ÷ ¹/₂T
Explanation:
The formula for velocity is distance covered ÷ time.
Neglecting air resistance;
If the ball's time of overall time flight is T, the time it will take for the second half/return trip is ¹/₂T.
If the ball's maximum height above its released point is H, the height will also be the distance it covered for the second part of the trip since the student caught the ball in the exact same place the ball was thrown. Hence, the distance for the second half of the trip will be H.
Since velocity = distance/time
The average velocity during the second half of the trip will be = H ÷ ¹/₂T
The gravitational force between them is 3000 gravity’s