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hichkok12 [17]
3 years ago
15

In an observational study researchers try not too ?

Physics
2 answers:
Ymorist [56]3 years ago
8 0

They try not to influence the subjects

Explanation:

jok3333 [9.3K]3 years ago
5 0
They try not to interfere or play any part j what happens rather they just look at it and see the results
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The immersed volume of body in a liquid depends on density of the liquid. TRUE or FALSE?​
miss Akunina [59]

Answer:

True - Archimedes Principle states that the buoyant force on an object is equal to the weight of the liquid displaced.

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2 years ago
A cyclist is moving at a speed of 15 m/s. If the combined mass of the bike and person is 100 kg,
MaRussiya [10]

Answer:

Explanation:

Momentum is equal to mass times velocity in kg and m/s, respectively. Therefore,

p = 100(15) so

p = 1500 \frac{kg*m}{s}

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3 years ago
Describe 2 ways that mass and weight are the same
navik [9.2K]
Anything that has mass has weight and anything that has weight has mass simple.
7 0
4 years ago
One group of students uses different methods to conserve water as listed below.
Deffense [45]
The best answer is b) <span>Method 1 and Method 3

Method 2, which is part of every other options, does involve using extra water because the dishwasher will necessarily use extra water, even if it is full when you use it. 
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3 0
4 years ago
The radioactive element polonium decays according to the law given below where Q0 is the initial amount and the time t is measur
kogti [31]

Answer:

1280 mg

Explanation:

Radioactive  decay is a phenomenon that occurs when a certain isotope of an element, said to be radioactive, decays, turning into a lighter nucleus and emitting radiation + energy in the process.

The radioactive decay of this isotope of polonium is described by the equation

Q(t)=Q_0 2^{-\frac{t}{140}}

where

Q(t) is the amount of polonium left after time t

Q_0 is the amount of polonium t time t = 0

140 is the half-life of the polonium, in days (it is the time it takes for the initial element to halve its amount)

IN this problem, we know that:

After t = 560 days, the amount of polonium left is Q(t)=80 mg. Therefore, we can re-arrange the equation, substituting t = 560 d, and solve for Q_0 to find the initial amount of polonium:

Q_0 = Q(t) \cdot 2^{\frac{t}{140}}=(80)\cdot 2^{\frac{560}{140}}=1280 mg

5 0
4 years ago
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