Average Velocity = Total Displacement / Total time
1st part of journey, 350 km at velocity 125 km/h
Time = 350 / 125 = 2.8 hours.
2nd part of journey, 220 km at velocity 115 km/h
Time = 220 / 115 = 1.9 hours
Average Velocity = Total Displacement / Total time
= (350 + 220) / (2.8 + 1.9)
= 570 / 4.7 ≈ 121.3 km/hr
Average Velocity ≈ 121 km/hr due south.
Option C.
<span>The initial velocity of the bike was 1.67 (vf)m/s. This is found by evaluating 7.5/4.5 which yields the velocity per unit of time which is equivalent to initial velocity.</span>
To solve this problem we will apply the expression of charge per unit of time in a capacitor with a given resistance. Mathematically said expression is given as

Here,
q = Charge
t = Time
R = Resistance
C = Capacitance
When the charge reach its half value it has passed 10ms, then the equation is,




We know that RC is equal to the time constant, then

Therefore the time constant for the process is about 14ms
Explanation:
the formula for momentum is denoted by p=mv where p is momentum, m is mass and v is velocity. thus, the velocity before impact would be 0.060 x 30 = 1.8 kg/ms
the second one would just be 0.060 x 20 0.72kg/ms
I'm not 100 percent sure this is correct but yeah
Answer:
false statement are C , F , D.
Explanation:
false statement are C , F , D.
a) triple bond consist of two π bond and one sigma bond.
b) in double bond one bond is σ bond and one is π bond.
c) end to end overlapping is in σ bond and electron density in σ bond lie between the nuclei.
true statements are A, B , E.
π bond restrict rotation is correct and then the statement of bond formation between s orbital is σ bond.