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4 years ago

A pulling force is called what? A. normal B. tension C. balanced D. compression

Physics

2 answers:

worty [1.4K]4 years ago

5 0

What i think the pulling forced called is , balanced force.

joja [24]4 years ago

3 0

<span>There is no special name for that. Physics is usually just concerned with "forces", and doesn't specify whether the force pushes or pulls. If you want to be more specific, you can just call it a "pulling force".
I hoped this was satisfying!:)</span>

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A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases

Mila [183]

Answer:

Rise in level of fluid is 0.11 m

Rise in level of fluid in case of mercury is 0.728 cm or 7.28 mm

Solution:

As per the question:

Density of oil, $\rho_{o} = 0.900\ g/cm^{3} = 900\ kg/m^{3}$

Change in Pressure in the tank, $\Delta P = 7.28\ mmHg$

Density of the mercury, $\rho_{m} = 13.6\ g/cm^{3} = 13600\ kg/m^{3}$

Now,

To calculate the rise in the level of fluid inside the manometer:

We know that:

1 mmHg = 133.332 Pa

Thus

$\Delta P = 7.28\ times 133.332 = 970.656\ Pa$

Also,

$\Delta P = \rho_{o} gh$

where

g = acceleration due to gravity

h = height of the fluid level

$970.656 = 900\times 9.8\times h$

h = 0.11 m

Now, if mercury is used:

$\Delta P = \rho_{m} gh$

$970.656 = 13600\times 9.8\times h$

h = 0.00728 m = 7.28 mm

3 0

4 years ago

A tree is 257 ft high. To the nearest tenth of a meter, how tall is it in meters? There are 3.28 ft in 1 m.

olga2289 [7]

Answer:

Height of tree = 78.35 meters.

Explanation:

We have

1 meter = 3.28 feet

That is

$1 ft = \frac{1}{3.28}=0.3048m$

Here height of tree = 257 ft

Height of tree = 257 x 0.3048 = 78.35 m

Height of tree = 78.35 meters.

7 0

4 years ago

You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.

olchik [2.2K]

Answer:

greater than your true weight

Explanation:

When going up in an elevator the acceleration of the elevator is added to the acceleration due to gravity. This will increase the reading on the scale.

The expression of the resultant weight will be

$N=m(a+g)$