Answer:
T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N
Explanation:
a.)
Period: It is already given in the question "oscillator repeats its motion every 0.372 s".
So T=0.372 s
b)
frequency= f = 1/ T
f = 1/ 0.372
f=2.7 Hz
c).
Angular frequency= w= 2πf
w= 2*π*2.7
w=16.9 rad/s
d)
Spring Constant:
As w=
⇒w²= k/m
⇒k= m*w²
⇒k= 0.628 * 16.9² N/m
⇒k=179.2 N/m
e)
The mass will have maximum speed when it passes through the mean position.
At mean position
Maximum elastic potential energy = Maximum kinetic energy
1/2 k A² = 1/2 m v² ( A is amplitude of oscillation)
⇒ v=
⇒ v= 
\
⇒ v= 8.78 m/s
f)
Maximum force will be exerted on the block when it is at maximum distance.
F= k* A ( A is amplitude of oscillation)
F= 179.2 * 0.27 N
F= 48.4 N
Answer:
Shaft
coiled
generators
Kinetic
Electrical
Explanation:
By using moving shaft and coiled wire together, electric generators create electricity. Electric generators essentially convert kinetic energy (the energy of motion) into electric energy.
The correct answer for the question that is being presented above is this one: "B. 13m."
The formula of wave velocity is this:
wave velocity = f * <span>λ
</span>λ = v / f
<span>λ</span> = 343m/s / 26Hz
λ = 13.20m .. ans (b)
Here are the following choices:
A. 5m
B. 13m
C. 28m
D. 58m
<span>d. The parallaxes beyond a few thousand light years are
too small to be measured with common instruments.
I'm not sure that parallax can even be used out to a few
thousand light years.
The NEAREST star to Earth has the BIGGEST parallax.
The star is Alpha Centauri. It's only 4 light years away
from us, and its parallax is 0.000206 of a degree !
I have no idea how astronomers can measure angles
so small ... and that's the BIGGEST parallax angle of
ANY star.</span>
Answer:
Epsilon Eridani
Explanation:
This is in the main sequence as you can see there is an area called "main sequence all you have to do is read all the stars and to see which one is in there and that is The epsilon eridani
