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AnnZ [28]
3 years ago
7

Which process produces rising air when mountains push the air upward?

Physics
2 answers:
Schach [20]3 years ago
7 0

Answer:

The answer is A) orographic lifting

Explanation:

kicyunya [14]3 years ago
5 0

Answer;

A. orographic lifting

Explanation;

Orographic lifting is a process that takes place when an air mass is forced from a low elevation to a higher elevation as it moves over rising terrain.

This can be explained by;  When air is blocked by mountains, it cannot go through these mountains, As it ascends or moves up the mountain, the air then cools as it rises and when it cools to its saturation point, the water vapor condenses and cloud forms.

These clouds formed  are known as orographic clouds, that develop in response to the lifting forced by the topography the earth.

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An airplane is flying in a horizontal circle at a speed of 480 km/h (). If its wings are tilted at angle =40° to the horizontal
german

Answer:

R = 2162 m

Explanation:

When wings of the airplane makes an angle of 40 degree with the horizontal so here we can say that force due to air is having two components

F_y = mg

F_x = \frac{mv^2}{R}

now we know that

F_y = F cos40

F_x = F sin40

also we know that

v = 480 km/h

v = 133.3 m/s

now plug in all data in above equations

tan 40 = \frac{v^2}{Rg}

R = \frac{v^2}{g tan40}

R = \frac{133.3^2}{9.8 tan40}

R = 2162 m

6 0
3 years ago
De acuerdo a la trayectoria que describe el movimiento de la
dusya [7]

Answer:

With a circle.

Explanation:

8 0
2 years ago
IF it possible for an object to move for 10 seconds at a high speed and end up with an average velocity of zero? true or false
marishachu [46]

True, if you move something forward at 100 miles an hour but your on something moving backwards 100 miles an hour you up staying in the same location, aka zero velocity.

4 0
3 years ago
Read 2 more answers
Force due to gravity. While JWST is in orbit, the Earth will be at a distance of 1.494 x 109 m from the telescope, and the Sun w
Alona [7]

Answer:

the gravitational force JWST will feel from the Sun is 37.785 Newton { leftward }

Explanation:

Given that;

distance of earth from the telescope r1 = 1.494 × 10⁹ m

and the Sun will be 1.49598 × 10¹¹ m further away

so r2 = r1 + 1.49598 × 10¹¹

r2 = 1.494 × 10⁹ m + 1.49598 × 10¹¹ m = 1.51092 × 10¹¹ m

mass of sun Ms = 1.9884 × 10³⁰ kg

mass of earth Me = 5.945× 10²⁴ kg

mass of JWST Mj = 6500 kg

What is the gravitational force JWST will feel from the Sun (strength and direction)?

the gravitational force of the sun will be attractive based on Newton law of gravitational force; so

Fjs = GMjMs / r2²

constant G = 6.674 × 10⁻¹¹ Nm²/kg²

Force on the JWST by the sun will be;

Fjs = GMjMs / r2² { leftward}

we substitute

Fjs = [(6.674 × 10⁻¹¹ Nm²/kg²)(6500 kg )(1.9884 × 10³⁰ kg)] / (1.51092 × 10¹¹ m)²

=  (8.62587804 × 10²³) / ( 2.28287925 × 10²² )

= 37.785 Newton { leftward }

Therefore, the gravitational force JWST will feel from the Sun is 37.785 Newton { leftward }

7 0
3 years ago
Help!
Evgen [1.6K]

Answer:

factory:

-mechanical energy

-nuclear energy

-gravitational energy

Explanation:

8 0
3 years ago
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