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Tamiku [17]
3 years ago
11

Write an equation in slope-intercept form for the line that is parallel to the line y = -4x + 5 and that passes through the give

n point (-8,5). Show your work.
Mathematics
1 answer:
harkovskaia [24]3 years ago
3 0
Since we know the slope intercept form is y=mx+b and that parallel lines have the same slope we know that the slope in our equation is going to be -4
we can plug in the point (-8,5) into y= -4x+b
in doing that we get 5= -4(-8)+b.
5=-4(-8)+b
5=32+b
subtract 32 from both sides to find b the (y-intercept)
5-32=-27
b=-27
bc the slope is -4 and the y-intercept is -27 the equation of the line that's parallel to y=-4x+5 and passes through the given point (-8,5) is y=-4x-27
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3 years ago
Please help me with these questions
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3. Answer: y = 4

<u>Step-by-step explanation:</u>

Need to find the slope (m):

  \dfrac{y_2-y_1}{x_2-x_1}

  \dfrac{4 - 4}{-3-1}

= \dfrac{0}{-4}

= 0

Now input ONE of the points (1, 4) and the slope (m = 0) into the Point-Slope formula:

y - y₁ = m(x - x₁)

y - 4 = 0(x - 1)

y - 4 = 0

y      = 4

********************************************************************

4. Answer: \bold{y = \dfrac{2}{3}x + 3}

<u>Step-by-step explanation:</u>

 y - y_1 = m(x - x_1)

 y - 1 = \dfrac{2}{3}(x - (-3))

 y - 1 = \dfrac{2}{3}(x + 3)

 y - 1 = \dfrac{2}{3}x + 2

 y = \dfrac{2}{3}x + 3


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