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Alex17521 [72]
3 years ago
7

1. Scientific _____________, or determine the value of, differing scientific

Mathematics
1 answer:
Kruka [31]3 years ago
7 0
Going for a shot at this...

1) method

2) factual evidence

3) theory

If you want try waiting for more answers but these answers are based on research!
You might be interested in
Solve the inequality for x. <br> 3<br> 2<br> x + 2 &gt; 32
Elden [556K]

Answer:

x > 30

Step-by-step explanation:

x + 2 > 32

Subtract 2 from each side

x + 2-2 > 32-2

x > 30

4 0
3 years ago
Read 2 more answers
Robert slices a large loaf of bread to make 12 sandwiches. He made 3 turkey sandwiches and 5 veggie sandwiches. The rest are ham
lions [1.4K]
We already know that there are 12 sandwiches.

If there are 3 turkey and 5 veggie then there's 8 out of 12 sandwiches that aren't ham.

12 sandwiches - 8 non-ham sandwiches = 4 ham sandwiches

Now we know there are 4/12 ham sandwiches

We need to simplify this now.
4/12 can be divided by 4

4 goes into 4 1 time and 4 goes into 12 3 times making the answer 1/3

1/3 of the sandwiches are ham.
3 0
3 years ago
FINDING AREA ON A COORDINATE PLANE
Fynjy0 [20]

Answer:

This is not descriptive at all..?

Step-by-step explanation:

We need a real question.

8 0
3 years ago
Help asap please :(<br><br> Find the surface area of the composite figure.
Liono4ka [1.6K]

Answer:

136 in²

Step-by-step explanation:

8x2=16

6x2=12

6x2=12

6x2=12

10x2=20

10x2=20

10x2=20

8x2=16

2x2=4

2x2=4

136 in²

8 0
2 years ago
A fair die is rolled 12 times. the number of times an even number occurs on the 12 rolls has
bonufazy [111]

Answer:

Step-by-step explanation:

For a fair die, there are six likely options; 1, 2, 3, 4, 5, and 6

the probability of a even number is 3/6 = 0.5

Since the results of the die roll is independent and each trial is mutually exclusive, the distribution to explain the probability of occurrence will follow a binomial distribution such that n is the number of trials

x = number of successful throws

therefore for a Binomial distribution where

P(X =x) = nCx . P^x . (1-P)^ (n-x)

since p = 0.5, and n = 12, the distribution follows

P(X = x) = 12Cx . 0.5^x . (1 - 0.5)^(12- x)

= 12Cx . 0.5^x . 0.5)^(12- x)

where x = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

since we are interested in the probability of the number of times an even number occurs

it can occur either as P(X = 0), P(X =1), P(X =2), P(X =3), P(X =4), P(X =5), P(X =6), P(X =7), P(X =8), P(X =9), P(X =10), P(X =11), and P(X =12)

For no even number in 12 rolls,

P(X = 0) = 12C0 . 0.5^0 . 0.5^(12- 0) = 0.000244

For one even number in 12 rolls,

P(X = 1) = 12C1 . 0.5^1 . 0.5^(12- 1) = 0.002930

For two even number in 12 rolls,

P(X = 2) = 12C2 . 0.5^2 . 0.5^(12- 2) = 0.016113  

For three even number in 12 rolls,

P(X = 3) = 12C3 . 0.5^3 . 0.5^(12- 3) = 0.053711  

For four even number in 12 rolls,

P(X = 4) = 12C4 . 0.5^4 . 0.5^(12- 4) = 0.120850

For five even number in 12 rolls,

P(X = 5) = 12C5 . 0.5^5 . 0.5^(12- 5) = 0.193359

For six even number in 12 rolls,

P(X = 6) = 12C6 . 0.5^6 . 0.5^(12- 6) = 0.225586

For seven even number in 12 rolls,

P(X = 7) = 12C7 . 0.5^7 . 0.5^(12- 7) = 0.193359

For eight even number in 12 rolls,

P(X = 8) = 12C8 . 0.5^8 . 0.5^(12- 8) = 0.120850

For nine even number in 12 rolls,

P(X = 9) = 12C9 . 0.5^9 . 0.5^(12- 9) = 0.053711

For ten even number in 12 rolls,

P(X = 10) = 12C10 . 0.5^10 . 0.5^(12- 10) = 0.016113

For eleven even number in 12 rolls,

P(X = 11) = 12C11 . 0.5^11 . 0.5^(12- 11) = 0.002930

For twelve even number in 12 rolls,

P(X = 12) = 12C12 . 0.5^12 . 0.5^(12- 12) = 0.000244

Final test summation[P(X)] =  1

i.e.

P(X = 0) + P(X =1) + P(X =2) + P(X =3) + P(X =4) + P(X =5) + P(X =6) + P(X =7) + P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) = 1

Hence since 0.000244 + 0.002930 + 0.016113 + 0.053711 + 0.120850 + 0.193359 + 0.225586 + 0.193359 + 0.120850 + 0.053711 + 0.016113 + 0.002930 + 0.000244 = 1.000000,

the probability value stands

7 0
3 years ago
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