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LiRa [457]
3 years ago
8

Pure water is neutral. What is the appropriate justification for this? Water has equal H+ and OH- ions, making its pH 7, which i

s considered a neutral pH. Water has more H+ than OH- ions, making its pH 5, which is considered a neutral pH. Water has more OH- than H+ ions, making its pH 8, which is considered a neutral pH.
Chemistry
1 answer:
ddd [48]3 years ago
6 0
<span>Water has equal H+ and OH- ions, making its pH 7, which is considered a neutral pH.</span>
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A sealed flask containing 1.0 mole of H2(g) and a sealed flask containing 2.0 moles of He(g) are at the same temperature. The tw
irinina [24]

Answer:

Pressure or Average Kinetic Energy

Explanation:

When dealing with sealed containers filled with gas, there are many variables to consider. Namely: pressure, temperature, volume, number of molecules present.

However, this question can be solved easily, without worrying too much about the other variables. Usually the case is that if there is a difference in pressure, there will be a difference in temperature, so the answer could be that both pressures must be equal.

Another way we could look at it is that the Average Kinetic Energies between the two containers have to be equal, and this will then lead to the temperatures being equal without worrying about other variables.

8 0
3 years ago
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6 0
3 years ago
Your observation and assessment data should help you _______ your curriculum A. change B. modify and individualize C. evaluate t
joja [24]
Hello,
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4 0
2 years ago
Read 2 more answers
What is the molar mass of an unknown gas with a density of 2.00 g/L at 1.00 atm and 25.0 °C?
soldier1979 [14.2K]

Answer:

Explanation:Explanation:

Your starting point here will be the ideal gas law equation

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

P

V

=

n

R

T

a

a

∣

∣

−−−−−−−−−−−−−−−

, where

P

- the pressure of the gas

V

- the volume it occupies

n

- the number of moles of gas

R

- the universal gas constant, usually given as

0.0821

atm

⋅

L

mol

⋅

K

T

- the absolute temperature of the gas

Now, you will have to manipulate this equation in order to find a relationship between the density of the gas,

ρ

, under those conditions for pressure and temperature, and its molar mass,

M

M

.

You know that the molar mass of a substance tells you the mass of exactly one mole of that substance. This means that for a given mass

m

of this gas, you can express its molar mass as the ratio between

m

and

n

, the number of moles it contains

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

M

M

=

m

n

a

a

∣

∣

−−−−−−−−−−−−−

(

1

)

Similarly, the density of the substance tells you the mass of exactly one unit of volume of that substance.

This means that for the mass

m

of this gas, you can express its density as the ratio between

m

and the volume it occupies

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

ρ

=

m

V

a

a

∣

∣

−−−−−−−−−−−

(

2

)

Plug equation

(

1

)

into the ideal gas law equation to get

P

V

=

m

M

M

⋅

R

T

Rearrange to get

P

V

⋅

M

M

=

m

⋅

R

T

P

⋅

M

M

=

m

V

⋅

R

T

M

M

=

m

V

⋅

R

T

P

Finally, use equation

(

2

)

to write

M

M

=

ρ

⋅

R

T

P

Convert the temperature of the gas from degrees Celsius to Kelvin then plug in your values to find

M

M

=

1.02

g

L

⋅

0.0821

atm

⋅

L

mol

⋅

K

⋅

(

273.15

+

37

)

K

0.990

atm

M

M

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

26.3 g mol

−

1

a

a

∣

∣

−−−−−−−−−−−−−−−−

I'll leave the answer rounded to three

7 0
3 years ago
The boiling process is considered to be____
Dmitry_Shevchenko [17]

your answer is <u>D</u><u>.</u><u> </u>physical change, because a new substance is not formed.

5 0
2 years ago
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