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Reika [66]
3 years ago
7

Is there a way for me to get extra switches to switch my home Xbox, I already used all five and the extra one too. If there is n

o way, please just comment:(
Chemistry
1 answer:
Anastaziya [24]3 years ago
5 0
I don’t think there is another way for you to get an extra switch from your Xbox sorry:((
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What is 108 g +10+5+3
natali 33 [55]

ANSWER : 108 + 10 = 118

118 + ( 5 + 3 )

118 + 8 = <u>1</u><u>2</u><u>6</u>

<u>=</u><u> </u><u>1</u><u>2</u><u>6</u><u> </u><u>g</u>

7 0
3 years ago
Suppose that the physical properties of two stars are identical in every way --- for example, same distance, same mass, same tem
larisa [96]

Answer:

By measuring it's Radical velocity using Doppler Phenomenon...

Explanation:

It is done by measuring the absorption spectrum produces by a star as a result of measuring Doppler's relative wavelength. The star with the lower speed must have lower absorption spectrum extent as compared to the faster one.

4 0
3 years ago
Give the name, atomic symbol, and group number of the element with each Z value, and classify it as a metal, metalloid, or nonme
Viktor [21]

Atomic number = 42

Name = Molybdenum

Atomic symbol  = Mo

Group number = VI(B)6

Mo = Metal

How to find all valves of Z=42?

Here, we are going to find out the name, symbol and group numbers element with the following Z value and their classification as a metal, metalloid, or nonmetal.

The atomic number of the element is 42

Therefore, the name of the element is Molybdenum

The atomic symbol of the element is Mo

The group number of  is VI(B)6

Mo is a metal

Hence, the element is  Molybdenum

Learn more about atomic symbol here :

brainly.com/question/930789

#SPJ4

5 0
1 year ago
Given the following information:Br2 bond energy = 193 kJ/mol F2 bond energy = 154 kJ/mol 1/2Br2(g) + 3/2F2(g) -&gt; BrF3(g) = –3
arlik [135]

Answer:

C) 712 KJ/mol

Explanation:

  • ΔH°r = Σ Eb broken - Σ Eb formed
  • 1/2Br2(g) + 3/2F2(g) → BrF3(g)

∴ ΔH°r = - 384 KJ/mol

∴ Br2 Eb = 193 KJ/mol

∴ F2 Eb = 154 KJ/mol

⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)

⇒ Σ Eb broken =  (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol

∴ Eb formed: Br-F

⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r

⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )

⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol

8 0
3 years ago
Which compound exhibits both cis trans and optical isomerism? A: CH3CH=CHCH2CH3B: CH3CHBrCH=CH2C: CH3CBr=CBrCH3D CH3CH2CHBrCH=CH
irinina [24]
CH3CHBrCH=CBrCH3D
I think
4 0
3 years ago
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