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2 years ago

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From each drop-down menu, a solid has (a definite volume and a definite shape), a Liquid has (a definite volume) and gas has ( non of the above)

<h3>The features of different states of Matter:</h3>

Matter is defined as anything that has weight and occupies space.

There are three states of matter that is in existence which include:

Solid: The particles of solid are closely packed together and vibrate around fixed axes. That is why they have a definite shape and volume.

Liquid: The particles of liquid, though attracted to each other,move freely over each other. That is why they have definite volume but not a definite shape.

Therefore, a liquid occupies the shape of its container.

Gas: The particles of gas contain scattered molecules that are dispersed across a given volume.

Therefore, a gas neither has a definite shape nor volume.

Learn more about matter here:

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The density of solid Ag is 10.5 g/cm3. How many atoms are present per cubic centimeter of Ag?

Sveta_85 [38]

Answer:

Unit cells which are present per cubic centimeter of Ag = $=1.45\times 10^{22}\ unit\ cells /cm^3$

Volume = $68.9\times 10^{-24}\ cm^3$

Edge length = $4.1\times 10^{-8}\ cm$

Explanation:

(a)

Given that:-

The density of the solid Ag = 10.5 g/cm³

Molar mass of silver = 107.8682 g/mol

So, Moles present per cm³ of Ag = $\frac{10.5\ g/cm^3}{107.8682\ g/mol}$ =0.0973 mol/cm³

Also, 1 mole = $6.023\times 10^{23}$ atoms.

So,

Atoms present per cm³ of Ag = $0.0973\ mol/cm^3\times 6.023\times 10^{23}\ atoms/mol=5.8\times 10^{22}\ atoms/cm^3$

Thus, answer = $5.8\times 10^{22}\ atoms/cm^3$

In FCC, the number of atoms in the unit cell = 4 unit cells

So,

Unit cells which are present per cubic centimeter of Ag = $\frac{5.8\times 10^{22}\ atoms/cm^3}{4}=1.45\times 10^{22}\ unit\ cells /cm^3$

<u>Unit cells which are present per cubic centimeter of Ag = $=1.45\times 10^{22}\ unit\ cells /cm^3$ </u>

(b)

The reciprocal of the unit cell/cm³ is the volume of the unit cell.

So, $Volume=\frac{1}{1.45\times 10^{22}\ unit\ cells /cm^3}=68.9\times 10^{-24}\ cm^3$

<u>Volume = $68.9\times 10^{-24}\ cm^3$ </u>

(c)

Also, Volume = ${(Edge\ length)}^3$

Thus, edge length = ${Volume}^{\frac{1}{3}}$ = $\left(68.9\times \:\:10^{-24}\right)^{\frac{1}{3}}\ cm=4.1\times 10^{-8}\ cm$

<u>Edge length = $4.1\times 10^{-8}\ cm$ </u>

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4 years ago

Natalia wants to test the effect of temperature on the rate of

Dimas [21]

Answer:

The independent variable is the effect of tempeture on the rate of photosynthesis

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3 years ago

¿Qué estudia la química orgánica?

Scorpion4ik [409]

Answer: el estudio de la síntesis, estructura, reactividad y propiedades del diverso grupo de compuestos químicos construidos principalmente de carbono

Explanation:Hope I helped:)

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3 years ago

What causes Brownian motion in colloids?

Ipatiy [6.2K]

Hey there!

Your answer is option A.

"Molecules of the dispersion medium colliding with dispersed phase particles" is what causes Brownian motion in colloids.

Hope this helps you.
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4 years ago

Read 2 more answers

A change in matter that produces new substances is called a _____. 1.mixture 2.physical change 3.solution 4.chemical change

12345 [234]

Answer:

Chemical Change

Explanation:

chemical bonds within the substance have been altered because a new substance has been produced. It cannot be a mixture because they do not involve changes in matter, it cannot be a physical change because they do not result in new substances, it is not a solution because those do not involve changes in matter.

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3 years ago