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Olegator [25]
3 years ago
11

Let’s say that you have a solvatochromic compound that appears red in a solvent. You dissolve the compound in another solvent an

d it changes to an orange color. Would this be considered a hypsochromic or bathchromic shift? Would the solvent be more polar or less than the first solvent? Explain.
Chemistry
1 answer:
KiRa [710]3 years ago
7 0

Answer:

Hypsochromic shift.

The second solvent is more polar.

Explanation:

Compound A + Solvent 1 = red

Compound A + Solvent 2 = orange

Since orange has a smaller wavelength than red, the electronic transition observed when the compound A is dissolved in solvent 2 has a higher energy.

A band transition to a lower wavelength and higher energy is called a hypsochromic shift.

The change in the color due to the solvent is called solvatochromism. Usually, when the hypsochromic shift is observed (negative solvatochromism) it means that the solvent is more polar.

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A canister has a fixed volume. If the pressure of the cannister is 1.5 atm at 25 Celsius, what is the new pressure if the temper
scoray [572]

Answer:

<u>d) 1.8 atm</u>

Explanation:

<u>According to Boyle's Law,</u>

  • P₁/T₁ = P₂/T₂

Here, we are given :

  1. <u>P₁ = 1.5 atm</u>
  2. <u>T₁ = 25°C = 298 K</u>
  3. <u>T₂ = 75°C = 348 K</u>

<u />

<u>Solving</u>

  • P₂ = P₁T₂/T₁
  • P₂ = 1.5 x 348 / 298
  • P₂ = 522/298
  • P₂ = <u>1.8 atm</u> (approximately)
3 0
2 years ago
How do elements differ going from left to right across a period on the periodic table?
Nuetrik [128]
Their atomic number increases
6 0
3 years ago
If you have 97 moles of pb (NO3)2 you can produce moles of KNO3
ladessa [460]

The given equation is already balanced. We can use the stoichiometric ratio given by the equation to find how many moles of KNO3 are produced. According to the equation, for every mole of Pb(NO3)2, 2 moles of KNO3 are produced.

97molPb\left(NO_3\right)_2\cdot\frac{2molKNO_3}{1molPb\left(NO_3\right)_2}=194molKNO_3

It means that 194moles of KNO3 are produced.

4 0
1 year ago
It is expected that a chemical reaction will occur when copper metal is combined with aqueous zinc sulfate. Explain why there wi
REY [17]

Answer:

E_{cell}= +ve, reaction is spontaneous

E_{cell}= -ve, reaction is non spontaneous

E_{cell}= 0, reaction is in equilibrium

Case 1: when copper metal is combined with aqueous zinc sulfate.

Cu+ZnSO_4\rightarrow Zn+CuSO_4

Here copper is undergoing oxidation ad thus acts as anode and zinc is undergoing reduction , thus acts as cathode.

E^o_{cell} = standard electrode potential =E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Cu^{2+}/Cu]}= +0.34V

E^0_{[Zn^{2+}/Zn]}= -0.76V

E^0=E^0_{[Zn^{2+}/Zn]}- E^0_{[Cu^{2+}/Cu]}

E^0=-0.76-(+0.34)=-1.10V

Thus as E_{cell} is negative , the reaction is non spontaneous.

Case 2: when zinc metal and aqueous copper sulfate solution are combined.

Zn+CuSO_4\rightarrow Cu+ZnSO_4

Here zinc is undergoing oxidation ad thus acts as anode and copper is undergoing reduction , thus acts as cathode.

E^o_{cell} = standard electrode potential =E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Cu^{2+}/Cu]}= +0.34V

E^0_{[Zn^{2+}/Zn]}= -0.76V

E^0=E^0_{[Cu^{2+}/Cu]}- E^0_{[Zn^{2+}/Zn]}

E^0=+0.34-(-0.76)=+1.10V

Thus as E_{cell} is positive , the reaction is spontaneous.

3 0
4 years ago
Something that an animal does that is driven by instinct is called a??
Lunna [17]

Answer:

2. Behavioral Adaption

Explanation:

I know about this, I think this is the answer. Try it out!!

5 0
3 years ago
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