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natita [175]
2 years ago
7

Which of the following best describes the rate of motion of a glacier?

Chemistry
2 answers:
Minchanka [31]2 years ago
8 0
Same speed as Continental drift

irga5000 [103]2 years ago
5 0
The answer is c very slowly :)
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Identify the number of significant figures in each value. 147,320 g
Sidana [21]
There are 5 significant figures in <span>147,320.</span>
4 0
2 years ago
Read 2 more answers
This is the chemical formula for carvone (the chemical that gives spearmint its flavor): An organic chemist has determined by me
xz_007 [3.2K]

The given question is incomplete. The complete question is :

This is the chemical formula for carvone (the chemical that gives spearmint its flavor) C_{10}H_{14}O: An organic chemist has determined by measurements that there are 27.3 moles of carbon in a sample of carvone. How many moles of oxygen are in the sample

Answer: 2.73 moles of oxygen are there in the sample.

Explanation:

The chemical formula of carvone is C_{10}H_{14}O.

This means:

When 10 moles of carbon are there in carvone , 1 mole of oxygen is there in carvone

Thus for 27.3 moles of carbon in carvone , \frac{1}{10}\times 27.3=2.73 mole of oxygen is there in carvone.

Thus 2.73 moles of oxygen are there in the sample.

6 0
2 years ago
What are the main reactants and products in a neutralization reaction?
blagie [28]

The reactants in the neutralization reaction are an acid and a base while the products are a salt and water.

7 0
3 years ago
A 10.0 mL sample of 0.25 M NaOH(aq) is titrated with 0.10 M HCl(aq) (adding HCl to NaOH). Determine which region on the titratio
Anna11 [10]

Answer:

1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.

2) The pH of the solution after adding HCl is 12.6

Explanation:

10.0 mL of 0.25 M NaOH(aq) react with 15.0 mL of 0.10 M HCl(aq). Let's calculate the moles of each reactant.

nNaOH=\frac{0.25mol}{L} .10.0 \times 10^{-3} L=2.5 \times 10^{-3}mol

nHCl=\frac{0.10mol}{L} \times 15.0 \times 10^{-3} L=1.5 \times 10^{-3}mol

There is an excess of NaOH so the mixture is before the equivalence point. When HCl completely reacts, we can calculate the moles in excess of NaOH.

                    NaOH       +       HCl       ⇒       NaCl      +         H₂O

Initial          2.5 × 10⁻³         1.5 × 10⁻³               0                      0

Reaction    -1.5 × 10⁻³        -1.5 × 10⁻³          1.5 × 10⁻³          1.5 × 10⁻³

Final            1.0 × 10⁻³               0                 1.5 × 10⁻³          1.5 × 10⁻³

The concentration of NaOH is:

[NaOH]=\frac{1.0 \times 10^{-3} mol }{25.0 \times 10^{-3} L} =0.040M

NaOH is a strong base so [OH⁻] = [NaOH].

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log 0.040 = 1.4

pH = 14 - pOH = 14 - 1.4 = 12.6

5 0
3 years ago
Compounds can not be separated by Response area means. Separating a compound requires a Response areareaction.
Aleks04 [339]

Answer:

use vinager

Explanation:

I did this heh :/

7 0
3 years ago
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