There are 1.93 x 10²⁴ particles
<h3>Further explanation</h3>Given
3.2 moles of Neon gas
Required
Number of particles
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
<em>1 mol = 6.02.10²³ particles </em>
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
So the number of particles for 3.2 moles :
N = 3.2 x 6.02.10²³
N = 1.93 x 10²⁴
or
we can describe it using Avogadro's number conversion factor
Answer:
0.0714 M for the given variables
Explanation:
The question is missing some data, but one of the original questions regarding this problem provides the following data:
Mass of copper(II) acetate:
Volume of the sodium chromate solution:
Molarity of the sodium chromate solution:
Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:
Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:
Moles of the sodium chromate solution would be found by multiplying its volume by molarity:
Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.
Write the net ionic equation for this reaction:
Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:
According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:
The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate: