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3 years ago

Three units put together in different patterns essentially make

Chemistry

2 answers:

DaniilM [7]3 years ago

5 0

Answer:

Three units, put together in different patterns make, essentially, everything.

Explanation:

Atoms are composed of three elementary particles, protons, neutrons and electrons. As a result Chemistry and Physics have reduced the complexity of the sensible world to incredible simplicity. Three units brought together in different patterns essentially do everything.

This is because everything we know that is touchable is matter and matter is composed of atoms that are composed of three units.

V125BC [204]3 years ago

3 0

The answer is everything.

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The rate of a hypothetical reaction involving L and M is found to double when the concentration of L is doubled and to increase

Semmy [17]

Answer: $Rate=k[L]^1[M]^2$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$L+M\rightarrow products$

$Rate=k[L]^x[M]^y$ (1)

k= rate constant

x = order with respect to L

y = order with respect to M

n =( x+y)= Total order

a) If [L] is doubled, the reaction rate will increase by a factor of 2:

$2\times Rate=k[2L]^x[M]^y$ (2)

b) If [M] is doubled, the reaction rate will increase by a factor of 4:

$4\times Rate=k[L]^x[2M]^y$ (3)

Dividing 2 by 1:

$\frac{2\times Rate}{Rate}=\frac{k[2L]^x[M]^y}{k[L]^x[M]^y}$

$2=2^x$

$x=1$

Dividing 3 by 1

$\frac{4\times Rate}{Rate}=\frac{k[L]^x[2M]^y}{k[L]^x[M]^y}$

$4=2^y$

$2^2=2^y$

$y=2$

Thus rate law is: $k[L]^1[M]^2$

4 0

4 years ago

A student dissolves of 15 g aniline in of a solvent with a density of . The student notices that the volume of the solvent does

VikaD [51]

The given question is incomplete. The complete question is ;

A student dissolves of 15 g aniline in 200 ml of a solvent with a density of 1.05 g/ml. The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.

Answer: The molarity is 0.81 M and molality is 0.82 m

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in ml = 200 ml

${\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol$

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{0.16\times 1000}{200}=0.81M$

Thus molarity is 0.81 M

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in g

${\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol$

Mass of solution = $Density\times Volume=1.05g/ml\times 200ml=210g$

mass of solvent = mass of solution - mass of solute = (210 - 15) g = 195 g

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.16\times 1000}{195g}=0.82mole/kg$

Therefore, the molality of solution is 0.82m

3 0

3 years ago

Radio waves are examples of electromagnetic waves. T or F

lesantik [10]

Answer:

the answer is true

Explanation:

3 0

4 years ago

A 50 gram sample of water is heated from 15 C to 125 C. How much energy in joules is required for this to occur?

LiRa [457]

Answer:

Explanation:

Using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat (Joules)

m = mass (grams)

c = specific heat capacity (J/g°C)

∆T = change in temperature

3 0

3 years ago

A solution is made by dissolving 21.5 g of NaOH in approximately 450 mL of water in a volumetric flask. The solution becomes qui

zzz [600]

Answer:

The answer to your question is: pH = 13.97

Explanation:

Data

NaOH = 21.5 g

Volume = 500 ml

pH = ?

Formula

Molarity = moles / volume (l)

pOH = -log [OH⁺]

pH = 14 - pOH

Moles of NaOH

MM NaOH = 23 + 16 + 1

= 40 g

40 g of NaOH ----------------- 1 mol

21.5 g of NaOH -------------- x

x = 0.538 moles

Molarity = 0.538/ 0.5

= 1.075 M

pOH = -log [1.075]

pOH = 0.0318

pH = 14 - 0.0318

pH = 13.97

4 0

3 years ago