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3 years ago

Which fatty acid salt is soluble in water solutions?

Chemistry

1 answer:

Oliga [24]3 years ago

4 0

Answer is (A)
Pottasium and Sodium salts are soluble in water. When these soaps are added to hard water. Hard water contains calcium or magnesium ions and they form Magnesium or Calcuim salts. These salts of magnesium and calcium precipitates out and are insoluble in water. This precipitation is called as dirt (the exact word for dirt is not acceptable here). This process is considered as the disadvantage of soap as well as using hard water.

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Which type of changes are melting, freezing, and boiling?

tatiyna

Answer:

Adding heat.

Decreasing and increasing temperatures.

Explanation:

4 0

2 years ago

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In the reaction BaCO3 + 2HNO3 + Ba(NO3)2 + CO2 + H2O, what mass of Ba(NO3)2 can be formed by combining 55 g BaCO3 and 26 g HNO3

Nataliya [291]

From the stoichiometry of the reaction, the mass of barium nitrate produced is 54.9 g.

<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

BaCO3 + 2HNO3 ------> Ba(NO3)2 + CO2 + H2O

Number of moles of BaCO3 = 55 g/197.34 g/mol = 0.28 moles

Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles

From the reaction equation;

1 mole of BaCO3 reacts with 2 moles of HNO3

0.28 moles of BaCO3 reacts with 0.28 moles × 2 moles/1 mole = 0.56 moles

There is not enough HNO3 hence it is the limiting reactant.

Number of moles of Ba(NO3)2 produced is obtained from;

2 moles of HNO3 yields 1 mole of Ba(NO3)2

0.41 moles of HNO3 yields 0.41 moles × 1 mole/2 moles

= 0.21 moles of Ba(NO3)2

Mass of Ba(NO3)2 = 0.21 moles × 261.337 g/mol = 54.9 g

Learn more about stoichiometry: brainly.com/question/9743981

8 0

2 years ago

Which of the following is a variable property for a gas ? Select all that apply.

disa [49]

C) volume
.........
The volume of gas depends on e.g. temperature and pressure.

8 0

3 years ago

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A researcher dilutes 30.0 ml of ethanol to 300.0 ml with distilled water. what is the percentage concentration by volume of the

Len [333]

Answer: 9.09 %

Explanation:

To calculate the percentage concentration by volume, we use the formula:

$\text{Volume percent of solution}=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100$

Volume of ethanol (solute) = 30 ml

Volume of water (solvent) = 300 ml

Volume of solution= volume of solute + volume of solution = 30+ 300 = 330 ml

Putting values in above equation, we get:

$\text{Volume percent of solution}=\frac{30}{30+300}\times 100=9.09\%$

Hence, the volume percent of solution will be 9.09 %.

3 0

3 years ago

Read 2 more answers

School Math. Homework.

Ksju [112]

Answer:

The answer is TRUE!!!

Explanation:

Please mark brainliest... btw try online school... you can do the easiest thing such as: learning photography, basic drawling, digital art and design, web design, painting for beginers, fitness, etc.

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3 years ago