Which fatty acid salt is soluble in water solutions?
1 answer:
Answer is (A)
Pottasium and Sodium salts are soluble in water. When these soaps are added to hard water. Hard water contains calcium or magnesium ions and they form Magnesium or Calcuim salts. These salts of magnesium and calcium precipitates out and are insoluble in water. This precipitation is called as dirt (the exact word for dirt is not acceptable here). This process is considered as the disadvantage of soap as well as using hard water.
Pottasium and Sodium salts are soluble in water. When these soaps are added to hard water. Hard water contains calcium or magnesium ions and they form Magnesium or Calcuim salts. These salts of magnesium and calcium precipitates out and are insoluble in water. This precipitation is called as dirt (the exact word for dirt is not acceptable here). This process is considered as the disadvantage of soap as well as using hard water.
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Answer:
118.22 atm
Explanation:
2SO₂(g) + O₂(g) ⇌ 2SO₃(g)
KP = 0.13 =
Where p(SO₃) is the partial pressure of SO₃, p(SO₂) is the partial pressure of SO₂ and p(O₂) is the partial pressure of O₂.
- With 2.00 mol SO₂ and 2.00 mol O₂ if there was a 100% yield of SO₃, then 2 moles of SO₃ would be produced and 1.00 mol of O₂ would remain.
- With a 71.0% yield, there are only 2*0.71 = 1.42 mol SO₃, the moles of SO₂ that didn't react would be 2 - 1.42 = 0.58; and the moles of O₂ that didn't react would be 2 - 1.42/2 = 1.29.
The total number of moles is 1.42 + 0.58 + 1.29 = 3.29. With that value we can calculate the molar fraction (X) of each component:
- XSO₂ = 0.58/3.29 = 0.176
- XO₂ = 1.29/3.29 = 0.392
- XSO₃ = 1.42/3.29 = 0.432
The partial pressure of each gas is equal to the total pressure (PT) multiplied by the molar fraction of each component.
- p(SO₂) = 0.176 * PT
- p(O₂) = 0.392 * PT
- p(SO₃) = 0.432 * PT
Rewriting KP and solving for PT: