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Helen [10]
3 years ago
5

Which molecule will have a double covalent bond? #3 #5 & #6

Chemistry
1 answer:
KatRina [158]3 years ago
4 0

Answer:the CO2 molecule has an excess of electron

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This is the chemical formula for carvone (the chemical that gives spearmint its flavor): An organic chemist has determined by me
xz_007 [3.2K]

The given question is incomplete. The complete question is :

This is the chemical formula for carvone (the chemical that gives spearmint its flavor) C_{10}H_{14}O: An organic chemist has determined by measurements that there are 27.3 moles of carbon in a sample of carvone. How many moles of oxygen are in the sample

Answer: 2.73 moles of oxygen are there in the sample.

Explanation:

The chemical formula of carvone is C_{10}H_{14}O.

This means:

When 10 moles of carbon are there in carvone , 1 mole of oxygen is there in carvone

Thus for 27.3 moles of carbon in carvone , \frac{1}{10}\times 27.3=2.73 mole of oxygen is there in carvone.

Thus 2.73 moles of oxygen are there in the sample.

6 0
3 years ago
How do exothermic and endothermic differ
Ber [7]

Answer:

Explanation:

exothermic reactions involve release of heat whereas endothermic reaction involve absorption of heat.

6 0
3 years ago
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Why is Cu+O=2CuO unbalanced ​
stepan [7]

Answer:

because the product of CuO contains 2 molecules so it is unbalanced

Explanation:

to balance it 2Cu+2O=4CuO now it is balanced

3 0
3 years ago
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4.
Bad White [126]

Answer:

thick, insulating fur

Explanation:

If an animal lives in a freezing climate, it makes sense logically that the animal would adapt and develop a layer of thick fur to keep its body insulated and maintain homeostasis.

Hope this helped and please consider a Brainliest! :)

5 0
3 years ago
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Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
rewona [7]
<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

      = 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0
3 years ago
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