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MrRa [10]
3 years ago
11

An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge denisity σ1 = 0.37 μC/m2. Another infini

te sheet of charge with uniform charge density σ2 = -0.19 μC/m2 is located at x = c = 28 cm.. An uncharged infinite conducting slab is placed halfway in between these sheets ( i.e., between x = 12 cm and x = 16 cm). What is Ex(P), the x-component of the electric field at point P, located at (x,y) = (6 cm, 0)?
Physics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

The x-component of the electric field at point P --  31,638.41

Explanation:

Given data:

charge density \sigma_1 =0.37 \muC/m^2

Another charge density \sigma_2 = -0.19 \mu C/m^2

Electric field due to infinite sheet of charge is given as E

E = \frac{\sigma}{2\epsilon}

E_{NET} = E_1 + E_2

             = \frac{\sigma_1}{2\epsilon} + \frac{\sigma_2}{2\epsilon}

            =  \frac{0.37\times 10^{-6}}{2\times 8.85\times 10^{-12}} + \frac{0.19\times 10^{-6}}{2\times 8.85\times 10^{-12}}

             = 31,638.41

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3 years ago
Why is it important for a muscle to be attached to a fixed origin at one end and a moving insertion at the other? Discuss how th
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