Question

An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge denisity σ1 = 0.37 μC/m2. Another infinite sheet of charge with uniform charge density σ2 = -0.19 μC/m2 is located at x = c = 28 cm.. An uncharged infinite conducting slab is placed halfway in between these sheets ( i.e., between x = 12 cm and x = 16 cm). What is Ex(P), the x-component of the electric field at point P, located at (x,y) = (6 cm, 0)?

Answer 1

Answer:

The x-component of the electric field at point P --  31,638.41

Explanation:

Given data:

charge density $\sigma_1 =0.37 \muC/m^2$

Another charge density $\sigma_2 = -0.19 \mu C/m^2$

Electric field due to infinite sheet of charge is given as E

$E = \frac{\sigma}{2\epsilon}$

$E_{NET} = E_1 + E_2$

             $= \frac{\sigma_1}{2\epsilon} + \frac{\sigma_2}{2\epsilon}$

            $= \frac{0.37\times 10^{-6}}{2\times 8.85\times 10^{-12}} + \frac{0.19\times 10^{-6}}{2\times 8.85\times 10^{-12}}$

             = 31,638.41