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2 years ago

PLease answer the thing and explain why is that...

Chemistry

1 answer:

iragen [17]2 years ago

4 0

Answer: i think its d

Explanation:

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I need help please with this chemistry work

Marysya12 [62]

Answer:

question 1: 3

question 2: the number of Valence electrons in the atom

hope it helps

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2 years ago

Consider 100.0-g samples of two different compounds consisting only of carbon and oxygen. one compound contains 27.2 g of carbon

Sliva [168]

This is a tricky question. All that matters are ratios of percentages, not percentages themselves. So no one should directly compare 27.2 with 42.9. We must and shall compare the ratios (27.2 to 72.8) and (42.9 to 57.1).

Take them both down to 1 to and see what happens.

Working out the formulas knowing atomic masses is a bit beside the point; this is how people first DISCOVERED the idea of atomic mass.

Carbon Oxygen

27.2g 72.8g (100-27.2)

Moles 27.2/12 72.8/16

2.27 4.55

Ratio 1 2

Do the same with the other

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3 years ago

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Ight i'm soo bored just wanna talk hit me up

ElenaW [278]

Answer:

hii

Explanation:

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2 years ago

Let’s say you have 3 UV active spots in the crude material and co-spot TLC plate. One has the same Rf value as the starting mate

Troyanec [42]

Answer:

Answer: (1R,2S) / (1S, 2R) , (1R,2R) / (1S, 2S)

Explanation:

Sodium borohydride reduction of benzoin will give four possible stereo isomers out of which are (1R,2S) - (1S, 2R) isomers and (1R,2R) - (1S, 2S) isomers which are known as enantiomers.

In general enantiomers show single spot in the TLC as they do not show any difference in Rf value (i.e) (1R,2S) - (1S, 2R) isomers show only one spot although they are two compounds and also (1R,2R) - (1S, 2S) isomers also show one spot. That is the reason why you are observing two spots in the TLC ( of reaction mixture) other than starting materilal.

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2 years ago

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A 0.885 M solution of KBr whose initial volume is 82.5 mL has more water added until its concentration is 0.500 M. What is the n

4vir4ik [10]

Answer:

$V_2=146mL$

Explanation:

Hello there!

In this case, since the equation for the calculation of dilutions is:

$M_1V_1=M_2V_2$

Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:

$V_2=\frac{M_1V_1}{M_2}=\frac{0.885M*82.5mL}{0.500M}\\\\V_2=146mL$

Best regards!

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2 years ago