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Kamila [148]
4 years ago
7

You will be helping Galileo perform the experiment to determine if objects with different mass fall at the same, or different, r

ates in the air and in a vacuum. Before you conduct your experiment, you need to form a hypothesis. A hypothesis is a prediction of what you think will happen in the experiment. The hypothesis is a statement that describes “if” a certain set of circumstances are present “then” there will be a specific result that will occur.
Record your hypothesis here:
Record the results from step one of the experiment (dropping the objects in the air):

First trial:

Second trial:

Third trial:
Record the results from step two of the experiment (dropping the objects in a vacuum):

First trial:

Second trial:

Third trial:
Did the experiment support your hypothesis? Using the data from your experiment, describe why you believe your hypothesis was either proven or disproven.
What forces were acting on the objects dropped in the air? What force was acting on the objects dropped in the vacuum?
Part Two: Comparing Forces
Choose two forces and compare and contrast these forces. You must provide two ways that they are alike and two ways that they are different. You may make a list, write in paragraph form, or make a chart.
Choose two forces and compare and contrast these forces. These must be different forces than used in the prior question. Provide two ways that they are similar and two ways that they are different. You may make a list, write it out, or make a chart.
Physics
1 answer:
Rashid [163]4 years ago
8 0

Answer:

First trial: Big ball dropped first, feather fell much later

Second trial: Big ball and small bell fell at same time

Third trial: small ball fell first, feather fell later

Explanation:

happy to help ya:)

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In the aerials competition in skiing, the competitors speed down a ramp that slopes sharply upward at the end. The sharp upward
11111nata11111 [884]

Answer:

u = 11.6 m/s

Explanation:

The end of a launch ramp is directed 63° above the horizontal. A skier attains a height of 10.9 m above the end of the ramp.

Maximum height, H = 10.9

Let v is the launch speed of the skier. The maximum height attained by the projectile is given by :

H=\dfrac{u^2\ sin^2\theta}{g}

10.9=\dfrac{u^2\ sin^2(63)}{9.8}

u = 11.6 m/s

So, the launch speed of the skier is 11.6 m/s. Hence, this is the required solution.

4 0
3 years ago
While running a 100m race, a runner runs from the 20m to 30m mark in 77 frames of a video record. If the video camera recorded d
Marrrta [24]

Answer:

Speed of the runner during video interval is 6.49 m/s

Explanation:

According to the problem,

Number of frames recorded by camera in 1 second = 50

Time takes by camera to record 1 frame = (1/50) s

Time taken by camera to record 77 frames, t = \frac{1}{50}\times 77 s

Distance covered by the runner during the video recording, d = 10 m

Speed, v = \frac{Distance}{time}=\frac{d}{t}

Substitute the values of d and t in the above equation.

v = \frac{10}{\frac{77}{50} }

v = 6.49 m/s

3 0
4 years ago
Small birds can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. (Figure 1) F
Katen [24]

Answer: 3.1107grams of fat.

Explanation:The speed to cover 800 km in 20 hours will be 40km/hr, Because

Speed =Distance/Time.

This is equal to 72,000 seconds. At a power consumption of 1.7 W, the bird will consume (1.7 X 72,000) =122,400 J of energy.

A gram of fat contains about (9.4 Calories X 4186 J/Calorie) ,=39348 joules of energy, the bird will need (122,400 / 39,348) = 3.1107 grams of fat.

4 0
3 years ago
How does kinetic energy affect the stopping distance of a small vehicle compared to a large vehicle?
RSB [31]
A small vehicle with less mass and with less Kinetic Energy will require less distance to stop than a large vehicle.
8 0
3 years ago
Billiard ball A strikes another ball B of the same mass, which is at rest, such that after the impact they move at angles ΘA and
Drupady [299]

Answer:

7.6427m/s

Explanation:

Given:v_a=4.7m/s, \theta_a=33.0\textdegree and \ v_b=4.5m/s

#Applying the conservation of momentum along the x-axis:mv_i=mv_acos\theta_a+mv_bcos\theta_b

#And along y-axis:

0=-sin\theta_a+mv_bsin\theta_b

#Solving  for \theta_b:

sin\rheta_b=\frac{v_a}{v_b}sin\theta_a=4.7/4.5\times sin33.0\textdegree\\=0.5688\\\therefore \theta_b=34.67\textdegree

#By substitution in the x-axis equation:

v_i=4.7cos 33.0\textdegree +4.5cos 34.67\textdegree\\=7.6427m/s

Hence the original speed of the ball before impact is 7.6427m/s

4 0
3 years ago
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