Answer:
u = 11.6 m/s
Explanation:
The end of a launch ramp is directed 63° above the horizontal. A skier attains a height of 10.9 m above the end of the ramp.
Maximum height, H = 10.9
Let v is the launch speed of the skier. The maximum height attained by the projectile is given by :


u = 11.6 m/s
So, the launch speed of the skier is 11.6 m/s. Hence, this is the required solution.
Answer:
Speed of the runner during video interval is 6.49 m/s
Explanation:
According to the problem,
Number of frames recorded by camera in 1 second = 50
Time takes by camera to record 1 frame = (1/50) s
Time taken by camera to record 77 frames, t =
s
Distance covered by the runner during the video recording, d = 10 m
Speed, v = 
Substitute the values of d and t in the above equation.
v = 
v = 6.49 m/s
Answer: 3.1107grams of fat.
Explanation:The speed to cover 800 km in 20 hours will be 40km/hr, Because
Speed =Distance/Time.
This is equal to 72,000 seconds. At a power consumption of 1.7 W, the bird will consume (1.7 X 72,000) =122,400 J of energy.
A gram of fat contains about (9.4 Calories X 4186 J/Calorie) ,=39348 joules of energy, the bird will need (122,400 / 39,348) = 3.1107 grams of fat.
A small vehicle with less mass and with less Kinetic Energy will require less distance to stop than a large vehicle.
Answer:
7.6427m/s
Explanation:
Given:
#Applying the conservation of momentum along the x-axis:
#And along y-axis:

#Solving for
:

#By substitution in the x-axis equation:

Hence the original speed of the ball before impact is 7.6427m/s