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Kamila [148]
3 years ago
7

You will be helping Galileo perform the experiment to determine if objects with different mass fall at the same, or different, r

ates in the air and in a vacuum. Before you conduct your experiment, you need to form a hypothesis. A hypothesis is a prediction of what you think will happen in the experiment. The hypothesis is a statement that describes “if” a certain set of circumstances are present “then” there will be a specific result that will occur.
Record your hypothesis here:
Record the results from step one of the experiment (dropping the objects in the air):

First trial:

Second trial:

Third trial:
Record the results from step two of the experiment (dropping the objects in a vacuum):

First trial:

Second trial:

Third trial:
Did the experiment support your hypothesis? Using the data from your experiment, describe why you believe your hypothesis was either proven or disproven.
What forces were acting on the objects dropped in the air? What force was acting on the objects dropped in the vacuum?
Part Two: Comparing Forces
Choose two forces and compare and contrast these forces. You must provide two ways that they are alike and two ways that they are different. You may make a list, write in paragraph form, or make a chart.
Choose two forces and compare and contrast these forces. These must be different forces than used in the prior question. Provide two ways that they are similar and two ways that they are different. You may make a list, write it out, or make a chart.
Physics
1 answer:
Rashid [163]3 years ago
8 0

Answer:

First trial: Big ball dropped first, feather fell much later

Second trial: Big ball and small bell fell at same time

Third trial: small ball fell first, feather fell later

Explanation:

happy to help ya:)

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If 36 grams of water is to be heated from 24.0°C to 48°C to make a cup of tea, how much heat must be added? The specific heat of
Vinvika [58]

We will have the following:

\begin{gathered} Q=mc\Delta T\Rightarrow Q=(36)(4.18)(48-24) \\  \\ \Rightarrow Q=3611.52 \end{gathered}

So, the heat to add is 3611.52 Joules.

3 0
1 year ago
A 40 kg girl and an 8.4 kg sled are on the surface of a frozen lake, 15 m apart. By means of a rope, the girl exerts a 5.2 N for
stealth61 [152]

Answer:

(a) a_s=0.62\frac{m}{s^2}

(b) a_s=0.13\frac{m}{s^2}

(c) x_f=2.6m

Explanation:

(a) According to Newton's second law, the acceleration of a body is directly proportional to the force exerted on it and inversely proportional to it's mass.

a_s=\frac{F}{m_s}\\a_s=\frac{5.2N}{8.4kg}\\a_s=0.62\frac{m}{s^2}

(b) According to Newton's third law, the force that the sled exerts on the girl is equal in magnitude but opposite in the direction of the force that the girl exerts on the sled:

a_g=\frac{F}{m_g}\\a_g=\frac{5.2N}{40kg}\\a_g=0.13\frac{m}{s^2}

(c) Using the kinematics equation:

x_f=x_0+v_0t \pm  \frac{at^2}{2}

For the girl, we have x_0=0 and v_0=0. So:

x_f_g=\frac{a_gt^2}{2}(1)

For the sled, we have v_0=0. So:

x_f_s=x_0_s-\frac{a_st^2}{2}(2)

When they meet, the final positions are the same. So, equaling (1) and (2) and solving for t:

x_0_s-\frac{a_st^2}{2}=\frac{a_st^2}{2}\\t^2(a_g+a_s)=2x_0_s\\t=\sqrt{\frac{2x_s_0}{a_g+a_s}}\\t=\sqrt{\frac{2(15m)}{0.13\frac{m}{s^2}+0.62\frac{m}{s^2}}}\\t=6.32s

Now, we solve (1) for x_f_g

x_f_g=\frac{0.13\frac{m}{s^2}(6.32s)^2}{2}\\x_f_g=2.6m\\x_f=2.6m

5 0
3 years ago
A car was moving at 30m/s when it hit a pole. It took 2 seconds to come to a stop. What was the car's acceleration in the crash
LuckyWell [14K]
A = v/t = 30/2 = 15 m/s
3 0
3 years ago
In a fusion reactor, the high temperature of the order of 108 k is required in order that what condition is met?
laila [671]
In order for a fusion reactor to function well, one of the important conditions to be met is a high temperature at 108 million Kelvin. This is six times hotter than the temperature of the sun's core. At this temperature, the element hydrogen's state is a plasma, not a gas, where the atoms are stripped of electrons and thus can move freely. This is an ideal condition to enable the reactor to function where it enables the hydrogen atoms to gather enough energy for the reaction which will occur in the later stages of the process. <span />
4 0
3 years ago
A 320-kg satellite experiences a gravitational force of 800 N. What is the radius of the satellite’s orbit? What is its altitude
Westkost [7]

Answer:

Radius of orbit = 3.992 × 10^{7} m

Altitude of Satellite =33541.9×  m

Explanation:

Formula for gravitational force for a satellite of mass m  moving in an orbit of radius r around a planet of mass M is given by;

F= G\frac{m M}{r^{2} }

Where G = Gravitational constant = 6.67408 × 10-11 \frac{m^{3} }{Kg sec^{2} }

We are given

F= 800 N

m = 320 Kg

M = 5.972 × 10^{24} Kg

G = 6.67408 × 10-11 \frac{m^{3} }{Kg sec^{2} }

We have to find radius r =?

putting values in formula;

==> 800 =6.67408 ×10^{-11}× 320 × 5.972 × 10^{24} / r^{2}

==> 800= 39.8576 × 10^{13} × 320 / r^{2}

==> 800 = 12754.43 × 10^{13} / r^{2}

==> r^{2} = 12754.43 × 10^{13} /800

==> r^{2}=15.94 × 10^{13}

==> r =  3.992 × 10^{7} m

==> r = 39920×10^{3} m

This is the distance of satellite from center of earth. To find altitude we need distance from surface of earth. So we will subtract radius of earth from this number to find altitude.

Radius of earth =6378.1 km = 6378.1 × 10^{3} m

Altitude = 39920×10^{3} - 6378.1 ×

3 0
3 years ago
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