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likoan [24]
3 years ago
15

This device combines multiple circuits at one end of a connection into a single complex circuit on a single wire. The signal is

then split into the individual connections on the other end.
Physics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

Multiplexer

Explanation:

-In electronics, a multiplexer, also known as a data, is a device that selects between several analog or digital input signals and forwards it to a single output line.

-This device combines multiple circuits at one end of a connection into a single complex circuit on a single wire.

-The selected signals is then transmitted at a higher speed.

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The scientist who used a prism to study light was _____.
DanielleElmas [232]
The scientist who used a prism to study light was Isaac Newton
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3 years ago
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Multiply the following numbers, using scientific notation and the correct amount of significant digits. 1.003 m⋅3.09 = _____ 3.0
lozanna [386]

Answer

correct answer is 3.10

Explanation:

in this question we have to multiply  two numbers 1.003 and 3.09.

1.003 has 4 significant digits and 3.09 has 3 significant digits so answer must have 3 significant digits.

1.003\times 3.09=3.09927

1.003\times 3.09=3.10              


Hope it will help you

3 0
3 years ago
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A point charge of 6.0 nC is placed at the center of a hollow spherical conductor (inner radius = 1.0 cm, outer radius = 2.0 cm)
egoroff_w [7]

Explanation:

The given data is as follows.

             q = 6.0 nC = 6 \times 10^{-9} C

         inner radius (r) = 1.0 cm = 0.01 m   (as 1 cm = 100 m)

So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.

Formula to calculate the charge density is as follows.

            \sigma = \frac{q_{in}}{A} .......... (1)

Since, area of the sphere is as follows.

               A = 4 \pi r^{2} ........... (2)

Hence, substituting equation (2) in equation (1) as follows.

      \sigma = \frac{q_{in}}{4 \pi r^{2}}

                   = \frac{6 \times 10^{-9} C}{4 \times 3.14 \times (0.01)^{2}}            

                   = 0.477 \times 10^{-5}

or,               = 4.77 \mu C/m^{2}

Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77 \mu C/m^{2}.

5 0
3 years ago
Determine the total impedance of an LRC circuit connected to a 10.0- kHz, 725-V (rms) source if L = 36.00 mL, R = 10.00 kΩ, and
SOVA2 [1]

Answer:

10042.6 ohm

Explanation:

f = 10 kHz = 10000 Hz, L = 36 mH = 0.036 H, R = 10 kilo Ohm = 10000 ohm

C = 5 nF = 5 x 10^-9 F

XL = 2 x π x f x L

XL = 2 x 3.14 x 10000 x 0.036 = 2260.8 ohm

Xc = 1 / ( 2 x π x f x C) = 1 / ( 2 x 3.14 x 10000 x 5 x 10^-9)

Xc = 3184.7 ohm

Total impedance is Z.

Z^2 = R^2  + (XL - Xc)^2

Z^2 = 10000^2 + ( 2260.8 - 3184.7 )^2

Z = 10042.6 ohm

4 0
3 years ago
Which statement is correct?
slega [8]

Answer:B

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Galilean transformation are only approximately correct,while Lorentz transformation are more exact

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