Answer:
2. [B] = [L]/[T] and [C] = [L]/[T]
Explanation:
I assume you mean this:
A = B² + 2B⁴/C²
Since you can't add numbers with different units (for example, you can't add seconds to meters), each term in the sum must have the same units as A.
B² = [L]²/[T]²
B = [L]/[T]
B⁴/C² = [L]²/[T]²
C²/B⁴ = [T]²/[L]²
C² = B⁴ [T]²/[L]²
C² = ([L]/[T])⁴ [T]²/[L]²
C² = [L]²/[T]²
C = [L]/[T]
Notice we ignore the 2 coefficient, which is unitless.
We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
where
is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
where
is the final speed of the sled
is the initial speed
is the distance covered
By rearranging the equation, we find d:
A). very large
B). very small
These are both wishy-washy words ... words that mean different things
to different people, and may even mean different things to the same person
at different times.
Even if everybody agreed on the meaning of these words, we wouldn't
have any idea which one may apply to the rover, because there's nothing
in the picture that gives any size reference ! We don't know from the picture
whether this thing is the size of a school book or a school bus. Or somewhere
in between.
C). very mathematical
What in the world does this mean ? ?
I don't see a single number or math symbol anywhere in the drawing.
I don't think this is the correct choice.
D). very complex
In the drawing, there are thirteen different labels of things,
and eight of them have such long names that only their initials
are shown.
This is one complicated combination of many different machines.
I think this is the best choice of description.
<span>principal quantum number (n) </span>represents the relative overall energy of each orbital
Hope this helps!
