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3 years ago

A 50 Ω resistor in a circuit has a current flowing through it of 2.0 A. What is the power dissipated by the resistor?

Physics

1 answer:

alukav5142 [94]3 years ago

4 0

Explanation:

A nichrome (ρ = 100x10-8 Ωm) wire has a diameter of 0.40 mm. ... A power line with a resistance of 2 ohms has a current of 80 A in it

1/8 Watt 50 kΩ resistor has 70 V applied.

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Which percentage best describes the visibility of a waxing crescent moon

Rus_ich [418]

Answer:

It be 0,1% - 49.9%

This is because the new moon is 0.0% and the first quarter is 50%.

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3 years ago

What type of change is wood to wood chip?

Vanyuwa [196]

Answer:

irriversible change.....

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3 years ago

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Against the park ranger's advice, a visitor at a national park throws a stone horizontally off the edge of a 86 m high cliff and

Drupady [299]

The initial horizontal velocity of the rock, in m/s is 21.241 m/s.

<h3>What is projectile?</h3>

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.

Time taken by the stone to reach the ground is

t = √2h/g

t = √(2x 86)/9.81

t = 4.19s

The horizontal velocity is

V(x) = Horizontal distance traveled / Time taken t

Put the values, we get

V(x) = 89 m/4.19 s

V(x) = 21.241 m/s

Thus, the horizontal velocity is 21.241 m/s

Learn more about projectile.

brainly.com/question/11422992

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2 years ago

The image shows one complete cycle of a mass on a spring in simple harmonic motion. An illustration of a mass on a vertical spri

Alja [10]

Answer:

D. "The net force is zero, so the acceleration is zero"

Explanation:

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3 years ago

A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu

Setler79 [48]

<h2>Given :</h2>

total charge = 9.0 mC = 0.009 C

Each electron has a charge of :

$1.6 \times 10 {}^{ - 19} \: C$

For producing 1 Cuolomb charge we need :

$\mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }$

$\dfrac{10 {}^{19} }{1.6}$

$\dfrac{10\times 10 {}^{19} }{16}$

$\dfrac{100 \times 10 {}^{18} }{16}$

$\mathrm{6.24 \times 10 {}^{18} \: \: electrons}$

Now, for producing 0.009 C of charge, the number of electrons required is :

$0.009 \times 6.24 \times {10}^{18}$

$0.05616 \times 10 {}^{18}$

$\mathrm{5.616 \times 10 {}^{16} \: \: electons}$

_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

$\mathrm{5.616 \times 10 {}^{16} \: \: electrons}$

Number of electrons passing through it in 1 Second is :

$\dfrac{5.616 \times {10}^{16} }{3.6}$

$\mathrm{1.56 \times 10 {}^{16} \: \: electrons}$

Now, in 10 seconds the number of electrons passing through it is :

$10 \times \mathrm{1.56 \times 10 {}^{16} \: \: }$

$\mathrm{1.56 \times 10 {}^{17} \: \: electrons}$

_____________________________

$\mathrm{ \#TeeNForeveR}$

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3 years ago