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ElenaW [278]
3 years ago
5

A 50 Ω resistor in a circuit has a current flowing through it of 2.0 A. What is the power dissipated by the resistor?

Physics
1 answer:
alukav5142 [94]3 years ago
4 0

Explanation:

A nichrome (ρ = 100x10-8 Ωm) wire has a diameter of 0.40 mm. ... A power line with a resistance of 2 ohms has a current of 80 A in it

1/8 Watt 50 kΩ resistor has 70 V applied.

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Si dos aparatos eléctricos que tienen diferente potencia funcionan durante el mismo tiempo, ¿ cual transformara mayor cantidad d
Brilliant_brown [7]

Answer: I dont undertand sorry

Explanatio

5 0
3 years ago
a ball rolls off the edge of a 2m high shelf at a speed of 5 m/s and hits the ground the taken to hit the ground is
RUDIKE [14]

Answer:

Explanation:

Use the one-dimensional equation

Δx = v_0t+\frac{1}{2}at^2 where delta x is the displacement of the object, v0 is the velocity of the object, a is the pull of gravity, and t is the time in seconds. That's our unknown.

Δx = -2 (negative because where it ends up is lower than the point at which it started),

v_0=5, and

a = -9.8

Filling in:

-2=5t+\frac{1}{2}(-9.8) t^2 and simplified a bit:

-2=5t-4.9 t^2

this should look hauntingly familiar (a quadratic, which is parabolic motion...very important in physics!!). We begin by getting everything on one side of the equals sign and solving for t by factoring:

-4.9 t^2+5t+2=0 (the 0 is also indicative of the object landing on the ground! Isn't this a beautiful thing, how it all just works so perfectly together?)

When you factor this however your math/physics teacher has you factoring you will get that

t = 1.3 sec and t = -.31 sec

Since we all know that time can NEVER be negative, it takes the ball 1.3 sec to hit the ground from a height of 2 m if it is rolling off the shelf at 5 m/s.

3 0
2 years ago
Explain what distinguishes acute and chronic sports injuries.
vfiekz [6]

Answer:

An acute injury is sudden and severe such as a broken bone. A chronic injury develops and worsens over an extended period of time like shin splints

Explanation:

3 0
3 years ago
Read 2 more answers
Two long parallel wires carry currents of 3.35 A and 6.99 A . The magnitude of the force per unit length acting on each wire is
Nady [450]

Answer:

244mm

Explanation:

I₁ = 3.35A

I₂ = 6.99A

μ₀ = 4π*10^-7

force per unit length (F/L) = 6.03*10⁻⁵N/m

B = (μ₀ I₁ I₂ )/ 2πr .........equation i

B = F / L ..........equation ii

equating equation i & ii,

F / L = (μ₀ I₁ I₂ )/ 2πr

Note F/L = B = F

F = (μ₀ I₁ I₂ ) / 2πr

2πr*F = (μ₀ I₁ I₂ )

r = (μ₀ I₁ I₂ ) / 2πF

r = (4π*10⁻⁷ * 3.35 * 6.99) / 2π * 6.03*10⁻⁵

r = 1.4713*10⁻⁵ / 6.03*10⁻⁵

r = 0.244m = 244mm

The distance between the wires is 244m

7 0
3 years ago
Read 2 more answers
.
Greeley [361]

Answer:

this is impossible for me

Explanation:

7 0
3 years ago
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