Eukaryotic, because there is a present cell membrane, organelles, and nucleus.
It takes to much energy and there's a lot of dirt
Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
Looking at the graph attached to this question, the correct option is this: THE MUSCLE WILL INCREASE IN TENSION TO A LEVEL GREATER THAN THAT MEASURED AT THE BEGINNING OF PHASE C.
Adding more load to a muscle increases the amount of work that a muscle is doing and increased work done by the muscles also results in increased muscle tension. <span />
