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Afina-wow [57]
3 years ago
10

Timothy has a fenced-in garden in the shape of a

Mathematics
1 answer:
sattari [20]3 years ago
7 0

Answer:

From the attached graphic we see that

rhombus side =   Sqr Root [(Long Diagonal / 2) ^ 2 + (Short Diagonal / 2) ^ 2]

rhombus side =   Sqr Root [(24/2)^2 + (18/2)^2]

rhombus side =   Sqr Root [144 + 81]

rhombus side =  Sqr Root (225)

rhombus side = 15 feet

Step-by-step explanation:

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Lauren invested $340 in an account paying an interest rate of 5.8% compounded monthly. Assuming no deposits or withdrawals are m
Viktor [21]

A = P(1 + rt)

A=340(1+.58x13)

2903.6

8 0
3 years ago
If f(x) =X +3, what is the value of f(3) and f(-2)?
ss7ja [257]
THIS ANSWER IS FOR f(3):
f(x)=x+3
f(3)=3+3
f(3)=6

THIS ANSWER IS FOR f(-2):
f(x)=x+3
f(-2)=-2+3
f(-2)=1
7 0
3 years ago
A hot air ballon descends at a rate of 320 feet per minute for 3 minutes. Use integers to calculate and represent the balloon's
Crank
You multiply 320 by 3 and the answer is 960
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3 years ago
Read 2 more answers
Evaluate the expression 4x^4 y^3 when x=1/5 and y=6
wariber [46]

Answer:

5.5296

Step-by-step explanation:

to evaluate the expression 4x^4 y^3 we would substitute the value of x and y into it and evaluate. since x = 1/5 and y = 6

4x^4 y^3

4 × x^4 × 4× y³

4 × (1/5)∧4 × 4 × 6³

4× (0.2)∧4 × 4 × 216

4 × 0.0016 × 864

0.0064 × 864

5.5296

5 0
3 years ago
A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What
vladimir2022 [97]

Answer:

The perimeter of the triangle is 12\ units

Step-by-step explanation:

Let

A(-3,1),B(1,1),C(1,-2)

we know that

The perimeter of triangle is equal to

P=AB+BC+AC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

A(-3,1),B(1,1)

substitute in the formula

AB=\sqrt{(1-1)^{2}+(1+3)^{2}}

AB=\sqrt{(0)^{2}+(4)^{2}}

AB=4\ units

step 2

Find the distance BC

B(1,1),C(1,-2)

substitute in the formula

BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}

BC=\sqrt{(-3)^{2}+(0)^{2}}

BC=3\ units

step 3

Find the distance AC

A(-3,1),C(1,-2)

substitute in the formula

AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}

AC=\sqrt{(-3)^{2}+(4)^{2}}

AC=5\ units

step 4

Find the perimeter

P=AB+BC+AC

substitute the values

P=4+3+5=12\ units

6 0
3 years ago
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