Answer:
1.88 M
Explanation:
The following data were obtained from the question:
Mole of NaCl = 0.47 mole
Volume of solution = 0.25L
Molarity =?
Molarity is defined as the mole of solute per unit litre of the solution. It can represented mathematically as:
Molarity = mole /Volume
Using the above formula, the molarity of the salt water solution can be obtained as follow:
Molarity = 0.47/0.25
Molarity = 1.88 M
Answer:
1.7927 mL
Explanation:
The mass of solid taken = 4.75 g
This solid contains 21.6 wt%
, thus,
Mass of
=
= 1.026 g
Molar mass of
= 261.337 g/mol
The formula for the calculation of moles is shown below:
Thus,

Considering the reaction as:

1 moles of
react with 1 mole of 
Thus,
0.003926 mole of
react with 0.003926 mole of 
Moles of
= 0.003926 mole
Also, considering:

Molarity = 2.19 M
So,

Volume = 0.0017927 L
Also, 1 L = 1000 mL
<u>So, volume = 1.7927 mL</u>
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The answer:
It is self Contained like a battery.
Freezing point depression is the phenomena that describes why adding a solute to a solvent results in the lowering of the freezing point of the solvent. ... Adding solute to a solvent will essentially dilute the solvent molecules, and according to Raoult's law, this leads to a decrease in vapor pressure.