1) State the balanced chemical reaction
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
2) State the molar ratios:
1 mol H2SO4 : 2 mol NaOH
3) Set the proportions using the number of moles of one rectant and x for the unknown one>
1 mol H2SO4 / 2 mol NaOH = x mol H2SO4 / 0.75 mol NaOH
=> x = 0.75 mol NaOH * [1 mol H2SO4 / 2 mol NaOH]
x = 0.375 mol H2SO4
4) Calculate the mass using the molar mass of H2SO4, MM.
MM = 2*1g/mol + 32.1 g/mol + 4*16 g/mol = 98.1 g/mol
mass = # of moles * molar mass = 0.375 mol * 98.1 g/mol = 36.79 g.
Answer: 36.8 grams
90 Joules
Use formula, q=mc∆t where m=mass c=specific heat ∆t=Tf-Ti
<span>you wanna use q=m*C*\Delta T\;
where Delta T=T_f-T_i for m, you wanna use the mass of the water not the octane because you're measuring the temp change of the water.</span>
Answer: 24.87g Al2O3
Explanation: Aluminum is our limiting reagent
First of all we need to convert the grams of aluminium to moles, then use the molar fraction of the balanced equation (4 moles of aluminium equals 2 of aluminum oxide).
If we made the same procedure with the oxigen we get a 0.273 mol of Al2O3, therefore the O2 is the excess reagent.
The last step is convert the moles of the limiting reagent to grams
And that´s it!
They all share the same atomic number (number of protons)