Answer:
an area of exposed rock after a glacier melts away
Explanation:
i took the test
<u>Answer:</u> The molar mass of the gas is 35.87 g/mol.
<u>Explanation:</u>
To calculate the mass of gas, we use the equation given by ideal gas:
PV = nRT
or,

where,
P = Pressure of gas = 945 mmHg
V = Volume of the gas = 0.35 L
m = Mass of gas = 0.527 g
M = Molar mass of gas = ? g/mo
R = Gas constant = 
T = Temperature of gas = ![88^oC=[88+273]=361K](https://tex.z-dn.net/?f=88%5EoC%3D%5B88%2B273%5D%3D361K)
Putting values in above equation, we get:

Hence, the molar mass of the gas is 35.87 g/mol.
Answer:
A. 0.038 g.
Explanation:
- The decay of carbon-14 is a first order reaction.
- The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
<u><em>The integration law of a first order reaction is:</em></u>
<em>kt = ln [Ao]/[A]</em>
k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.
t is the time = 17,190 years.
[Ao] is the initial concentration of carbon-14 = 0.300 g.
[A] is the remaining concentration of carbon-14 = ??? g.
∵ kt = ln [Ao]/[A]
∴ (1.21 x 10⁻⁴ year⁻¹)(17,190 years) = ln (0.300 g)/[A]
2.08 = ln (0.300 g)/[A]
Taking exponential for both sides:
8.0 = (0.300 g)/[A]
<em>∴ [A] = 0.0375 g ≅ 0.038 g</em>
Based on the calculations, the mass of Aluminum in 4.85 × 10²² atoms is equal to 2.1762 grams.
<h3>How to calculate the mass of Aluminum?</h3>
In order to determine the mass of Aluminum, we would calculate the number of atoms in 1 mole of an Aluminum atom in accordance with Avogadro's constant.
1 mole of Aluminum atom = 6.02 × 10²³ molecules
X moles of Aluminum atom = 4.85 × 10²² molecules
Cross-multiplying, we have:
X = 4.85 × 10²²/6.02 × 10²³
X = 0.0806 moles.
Mass = Molar mass × Number of moles
Mass = 27 × 0.0806
Mass = 2.1762 grams.
Read more on moles here: brainly.com/question/3173452
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