Answer:
tin (IV) oxide octahydrate contains 8 part water
What is the percent composition of water found in tin (IV) oxide octahydrate?
Answer:
73.73°C is the final temperature of the coffee.
Explanation:
Heat lost by the coffee = Q
Mass of the coffee = m
Volume of coffee = V =
Density of water = Density of coffee solution = d = 1 g/mL (given)


Heat capacity of the coffee is equal to that of water= c = 4.18 J/g°C
Initial temperature of the coffee = 
Final temperature of the coffee = T

Heat required to melt 11 grams of melt ice = Q'
Latent heat of ice = 

Heat absorbed by the ice after melting = q
Mass of ice melted into water = m' = 11 g
Heat capacity of water = c = 4.18 J/g°C
Initial temperature of water =
= 0°C
Final temperature of water = T

According law of conservation of energy , energy lost by coffee will equal to heat required to melt ice and further to raise the temperature of water.



On solving we get:
T = 73.73°C
73.73°C is the final temperature of the coffee.
By using ICE table:
CH3NH3+ + H2O → CH3NH4 2+ + OH-
initial 0.175 0 0
change -X +X +X
Equ (0.175-X) X X
when: Ka = Kw / Kb
= (1 x 10^-14) / (4.4 x 10^-4) = 2.3 x 10^-11
when Ka = [CH3NH42+][OH-] / [CH3NH3+]
by substitution:
2.3 x 10^-11 = X^2 / (0.175 - X ) by solving for X
∴ X = 2 x 10^-6
∴[OH-] = 2 x 10^-6
∴POH = -㏒[OH-]
= -㏒(2 x 10^-6)
= 5.7
when PH + POH = 14
∴PH = 14 - 5.7 = 8.3