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3 years ago

What is the mass number of an ion with 107 electrons, 159 neutrons, and a +1 charge? express your answer as an integer?

1 answer:

6 0

The mass number of an ion is calculated by adding the neutrons and electrons together. In this case 159+107=266. However, since this ion has a +1 charge, you must add 1 to the electrons. This would give a total mass of 267.

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How many mass would be contained in 0.01mol of NaOH

8_murik_8 [283]

Answer:

∴ No. of atoms in 0.01 moles of NaOH = 6.02×10

×0.01=6.02×10

3 0

2 years ago

when 6.0 mol of oxygen are confined in a 36L vessel at 196°c, the pressure is 8atm. what is the new pressure for oxygen expands

kykrilka [37]

Answer: The new pressure for oxygen gas is 6 atm.

Explanation:

To calculate the new pressure of the gas, we use the equation given by Boyle's Law.

This law states that the pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

Mathematically,

$P\propto \frac{1}{V}$

or,

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are the initial pressure and volume of the gas.

$P_2\text{ and }V_2$ are the final pressure and volume of the gas.

We are given:

$P_1=8atm\\V_1=36L\\P_2=?atm\\V_2=48L$

Putting values in above equation, we get:

$8atm\times 36L=P_2\times 48L\\\\P_2=6atm$

Hence, the new pressure for oxygen gas is 6 atm.

8 0

3 years ago

Calculate the ph of a buffer that is 0.145 m hc2h3o2 and 0.202 m kc2h3o2. The ka for hc2h3o2 is 1.8 × 10-5.

koban [17]

Answer:

pH = 4.8

Explanation:

A buffer is formed by a weak acid (0.145 M HC₂H₃O₂) and its conjugate base (0.202 M C₂H₃O₂⁻ coming from 0.202 M KC₂H₃O₂). The pH of a buffer system can be calculated using Henderson-Hasselbalch's equation.

$pH = pKa + log\frac{[base]}{[acid]} \\pH = -log(1.8 \times 10^{-5} )+log(\frac{0.202M}{0.145M} )\\pH=4.8$

6 0

3 years ago

Suppose you were to make a ring from a single strand of gold atoms. How many gold atoms would be required to make such a ring? H

Rudiy27

Let us assume that the ring is a size 7 ring, which has a circumference of 54.3 millimeters. Converting this to centimeters, the circumference of the ring is:

54.3 mm = 5.43 cm

Now, we determine the number of gold atoms that will be present in this:

5.43 / 1 x 10⁻⁹

There will be 5.43 x 10⁹ atoms

We now determine the number of moles this is by:

one mole = 6.02 x 10²³ atoms

Moles = 5.43 x 10⁹ / 6.02 x 10²³
Moles = 9.01 x 10⁻¹⁵ moles

The molar mass of gold is 197 g/mol

The mass is 9.01 x 10⁻¹⁵ * 197

The mass of the strand is 1.76 x 10⁻¹² grams

8 0

3 years ago

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Complete the following radioactive decay problem.

zzz [600]

I think it’s the third option

7 0

2 years ago

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