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3 years ago

How does the shape of the moon change over 4 weeks

1 answer:

4 0

Answer: The Moon appears to change shape because we see different amounts of the lit part as the Moon orbits Earth. ... As it moves around Earth, more and more of the lit side comes into view. Then it begins to disappear again. It takes 29.5 days for the Moon to orbit Earth.

Explanation:look it up lol

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A coil has N turns enclosing an area of A. In a physics laboratory experiment, the coil is rotated during the time interval Δt f

scoray [572]

Answer:

$\dfrac{NBA}{\Delta t}$

Explanation:

B = Magnetic field

A = Area

$\theta$ = Angle

t = Time taken

Before rotation the magnetic flux is given by

$\phi_i=BAsin\theta\\\Rightarrow \phi_i=BAsin90\\\Rightarrow \phi_i=BA$

Magnetic flux is BA

After rotation the magnetic flux is given by

$\phi_i=BAsin\theta\\\Rightarrow \phi_i=BAsin0\\\Rightarrow \phi_i=0$

The magnetic flux is 0

Magnitude of emf is given by

$\epsilon=NA\dfrac{d\phi}{dt}\\\Rightarrow \epsilon=\dfrac{NBA}{\Delta t}$

The magnitude of the average emf induced in the entire coil is $\dfrac{NBA}{\Delta t}$

4 0

3 years ago

Earth is about 150 million kilometers from the Sun, and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Us

EleoNora [17]

3) Earth is about 150 million km from the Sun, and the apparent brightness of the Sun in our sky is about 1,300 watts per square meter. Determine the apparent brightness we would measure for the Sun if we were located five times Earth's distance from the Sun. Answer: The Sun would appear 1/25 times as bright.

4 0

4 years ago

Read 2 more answers

A rock with a mass of 16 kilograms is put aboard an airplane in New York City and flown to Boston. How much work does the gravit

Law Incorporation [45]

The work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.

<u>The given parameter include:</u>

the mass of the object, m₁ = 16 kg

Note: the mass of the earth, m₂ = 5.972 x 10²⁴ kg

The work done by the gravitational field of the earth is given as;

Work done = gravitational force (F) x radius of the earth (R)

$Work \ done = \frac{Gm_1m_2}{R^2} \times R\\\\Work \ done = \frac{Gm_1m_2}{R} \\\\where;\\\\R \ is \ the \ radius \ of \ the \ earth = 6,378 \ km = 6,378,000 \ m\\\\G \ is \ the \ universal \ gravitation \ constant = 6.674 \times 10^{-11} Nm^2/kg^2\ \\\\Work \ done = \frac{(6.674 \times 10^{-11} ) \times (5.972\times 10^{24}) \times (16)}{6,378,000 } \\\\Work \ done = 9.998 \times 10^{8} \ J$

Therefore, the work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.

<u>To learn more about work done by gravitational field of the earth visit</u>: brainly.com/question/13934028

7 0

3 years ago

What do you mean by magnitude of an electric field due to a point charge. State its SI unit.

Vanyuwa [196]

Electric field strength is the force acting on a 1 Coulomb of positive change at that point. It is measured in Newton per Coulomb.

3 0

3 years ago

Why does a sound come out when you blow into a bottle?

ycow [4]

Answer:

sound comes out when you blow into a bottle because it reflects form the surface of the bottle.

I think that this answer will help you

8 0

3 years ago

Read 2 more answers