Question

A 3.0 L cylinder is heated from an initial temperature of 273 K at a pressure of 105 kPa to a final temperature of 381 K. 381 K. Assuming the amount of gas and the volume remain the same, what is the pressure (in kilopascals) of the cylinder after being heated?

Answer 1

Answer:

${P_2}=146.53\ kPa$

Explanation:

Volume ,V = 3 L

Initial temperature ,T₁ = 273 K

Initial pressure ,P₁ = 105 kPa

Final temperature ,T₂ = 381 K

Lets take final pressure =P₂

We know that ,If the volume of the gas is constant ,then we can say that

$\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}$

${P_2}=P_1\times \dfrac{T_2}{T_1}$

Now by putting the values in the above equation we get

${P_2}=105\times \dfrac{381}{273}\ kPa$

${P_2}=146.53\ kPa$

Therefore the final pressure will be 146.53 kPa.