Ok so I got the answer,and I’m confident it’s right.The answer is I=0
Answer:
E = 3.81×10 ⁻²¹ J
Explanation:
Given data:
Frequency of photon = 5.75 ×10¹² Hz
Plancks constant = 6.626 ×10⁻³⁴ Js
Energy of photon = ?
Solution:
E = h×f
E = 6.626 ×10⁻³⁴ Js × 5.75 ×10¹² s⁻¹
E = 38.1×10 ⁻²² J
E = 3.81×10 ⁻²¹ J
The solution would be like this for this specific problem:
<span>Given:
</span>66.0 g of carbon monoxide
reaction 2 C + O2 → 2 CO
<span>mol e= mass / molar mass <span>
<span>mole of 2CO = 66.0g / (12.011 15.999)g / mol </span>
mole of 2CO = 2.36 (CO and C has a 1:1 mole ratio)
mole of 2CO = 2.36 -> mole of 1 CO = 2.36 / 2 = 1.18
<span>We got 2 moles of C, thus 1.18 x 2 = 2.36
So, we 2.36 </span>moles of carbon are needed to produce 66.0 g of carbon monoxide in the </span>reaction
2 C + O2 → 2 CO.</span>
<span>To add, Carbon nonmetallic
and tetravalent, thus, making four electrons available to form covalent
chemical bonds. </span>
Answer:
92.2 m
Explanation:
Given that:=
The breadth = 304 mm
Height = 0.014 mm
Let Length = x mm
Volume = 
Thus,
Volume = 
Also, 1 mm³ = 0.001 cm³
So, volume = 0.004256 cm³
Given that density = 2.7 g/cm³
Mass = 1.06 kg = 1060 g
So,
So,
0.004256*x = 392.59
x = 92243.89 mm
Length of foil = 92243.89 mm = 92.2 m
The action that could slow a chemical reaction rate is adding
more of a substance to a mixture. The answer is letter d. It does not give time
for the rest of the reactants to be consumed because you are adding more of it
causing to slow the reaction.
