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4 years ago

50 POINTS FOR THE CORRECT ANSWER SOMEONE HELP ME ON THIS QUESTION PLEASE !!!!!!

Chemistry

2 answers:

oee [108]4 years ago

7 0

Answer:

it is positive and it reacts

KatRina [158]4 years ago

7 0

Positive
Spontaneous reaction
You also can find this on google

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Is the number 5x10 to the power of -4 greater than or less than 1.0?

Vinvika [58]

Greater than, I believe. 5x10 = 50. -4 is the opposite of +4 and 1.0 is just like the positive number one.

4 0

4 years ago

Read 2 more answers

Whats the number of moles of O2(g) needed to completely react with 8 moles of CO(g).

slava [35]

A mole of CO2 = 2 moles of O2
8 CO moles x 2 =

16 moles

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3 years ago

A food substance kept at 0Â°C becomes rotten (as determined by a good quantitative test) in 8.3 days. The same food rots in 10.6

ZanzabumX [31]

Answer:

1. 67.2 kJ/mol

Explanation:

Using the derived expression from Arrhenius Equation

$In \ (\frac{k_2}{k_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})$

Given that:

time $t_1$ = 8.3 days = (8.3 × 24 ) hours = 199.2 hours

time $t_2$ = 10.6 hours

Temperature $T_1$ = 0° C = (0+273 )K = 273 K

Temperature $T_2$ = 30° C = (30+ 273) = 303 K

Rate = 8.314 J / mol

Since $(\frac{k_2}{k_1}=\frac{t_2}{t_1})$

Then we can rewrite the above expression as:

$In \ (\frac{t_2}{t_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})$

$In \ (\frac{199.2}{10.6}) = \frac{E_a}{8.314}(\frac{303-273}{273*303})$

$2.934 = \frac{E_a}{8.314}(\frac{30}{82719})$

$2.934 = \frac{30E_a}{687725.766}$

$30E_a = 2.934 *687725.766$

$E_a = \frac{2.934 *687725.766}{30}$

$E_a =67255.58 \ J/mol$

$E_a =67.2 \ kJ/mol$

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3 years ago

A) ¿De qué trata el cuento que leíste?<br>

NISA [10]

No hablo espanol could you put it in English?

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3 years ago

What kind of intermolecular force is between hydrogen sulfide and hydrogen iodide?

RUDIKE [14]

I will have to go with carbon monoxide

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3 years ago