Using deep-sea sediment cores found that Milankovitch cycles correspond with periods of major climate change over the past 450,000 years, with Ice Ages occurring when Earth was undergoing different stages of orbital variation.
Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
Answer:
go outside and ponder your life choices dork.
The rate in m/s is 5.2 * 10^-4 m/s.
<h3>What is the rate in m/s?</h3>
We know that the speed is given as the ratio of the distance covered to the time taken. In this case, we have been told that the rate at which the tide rises is 6.08 ft per hour. We would now need to convert the rate from 6.08 ft per hour to m/s.
Now;
We know that;
1 foot/hour = 8.5 * 10^-5 m/s
6.08 ft per hour = 6.08 ft per hour * 8.5 * 10^-5 m/s/1 foot/hour
= 5.2 * 10^-4 m/s
Learn more about speed:brainly.com/question/28224010
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