Answer:
The answer is
<h2>11.73 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
![volume = \frac{mass}{density}](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7Bmass%7D%7Bdensity%7D%20)
From the question
mass of object = 30.5 g
Density = 2.6 g/cm³
The volume is
![volume = \frac{30.5}{2.6} \\ = 11.7307692...](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7B30.5%7D%7B2.6%7D%20%20%5C%5C%20%20%3D%2011.7307692...)
We have the final answer as
<h3>11.73 mL</h3>
Hope this helps you
Answer:
HCl conc.= 6.0mol/L
Explanation:
From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,
Answer:
d.) granulated
Because the granulated sugar has a greater surface area.
Answer:
I don't know what you're saying cuz give me the brainless answer please
Answer:
Mass of C₂H₄N₂ produced = 3.64 g
Explanation:
The balanced chemical equation for the reaction is given below:
3CH₄ (g) + 5CO₂ (g) + 8NH₃ (g) → 4C₂H₄N₂ (g) + 10H₂O (g)
From the equation, 3 moles of CH₄ reacts with 5 moles of CO₂ and 8 moles of NH₃ to produce 4 moles of C₂H₄N₂ and 10 moles of H₂O
Molar masses of the compounds are given below below:
CH₄ = 16 g/mol; CO₂ = 44 g/mol; NH3 = 17 g/mol; C₂H₄N₂ = 56 g/mol; H₂O g/mol
Comparing the mole ratios of the reacting masses;
CH₄ = 1.65/16 = 0.103
CO₂ = 13.5/44 = 0.307
NH₃ = 2.21/17 = 0.130
converting to whole number ratios by dividing with the smallest ratio
CH₄ = 0.103/0.103 = 1
CO₂ = 0.307/0.103 = 3
NH₃ = 0.130/0.103 = 1.3
Multiplying through with 5
CH₄ = 1 × 5 = 5
CO₂ = 3 × 5 = 15
NH₃ = 1.3 × 5 = 6.5
Therefore, the limiting reactant is NH₃
8 × 17 g (136 g) of NH₃ reacts to produce 4 × 56 g (224 g) of C₂H₄N₂
Therefore, 2.21 g of NH₃ will produce (2.21 × 224)/136 g of C₂H₄N₂ = 3.64 g of C₂H₄N₂
Mass of C₂H₄N₂ produced = 3.64 g