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3 years ago

Similarities between pluton and pegmatite

1 answer:

7 0

Plutons are large chambers of magma under grown

pegmatites generally form in pluton so it cools slow enough to make the crystals big enough to be classified as pegmatite and not just granite

You might be interested in

Is xenon (xe) more or less reactive than bromine (br)? why?

galben [10]

Answer:

Xenon is less reactive.

Explanation:

Xenon is a noble gas with 8 valence electrons whereas bromine is a halogen with 7 and is very reactive.

7 0

3 years ago

A weather balloon is filled with helium that occupies a volume of 5.57 104 L at 0.995 atm and 32.0°C. After it is released, it r

Alchen [17]

6.52 × 10⁴ L. (3 sig. fig.)

<h3>Explanation</h3>

Helium is a noble gas. The interaction between two helium molecules is rather weak, which makes the gas rather "ideal."

Consider the ideal gas law:

$P\cdot V = n\cdot R\cdot T$ ,

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of gas particles in the gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas in degrees Kelvins.

The question is asking for the final volume $V$ of the gas. Rearrange the ideal gas equation for volume:

$V = \dfrac{n \cdot R \cdot T}{P}$ .

Both the temperature of the gas, $T$ , and the pressure on the gas changed in this process. To find the new volume of the gas, change one variable at a time.

Start with the absolute temperature of the gas:

$T_0 = (32.0 + 273.15) \;\text{K} = 305.15\;\text{K}$ ,
$T_1 = (-14.5 + 273.15) \;\text{K} = 258.65\;\text{K}$ .

The volume of the gas is proportional to its temperature if both $n$ and $P$ stay constant.

$n$ won't change unless the balloon leaks, and
consider $P$ to be constant, for calculations that include $T$ .

$V_1 = V_0 \cdot \dfrac{T_1}{T_2} = 5.57\times 10^{4}\;\text{L}\times \dfrac{258.65\;\textbf{K}}{305.15\;\textbf{K}} = 4.72122\times 10^{4}\;\text{L}$ .

Now, keep the temperature at $T_1 =258.65\;\text{K}$ and change the pressure on the gas:

$P_1 = 0.995\;\text{atm}$ ,
$P_2 = 0.720\;\text{atm}$ .

The volume of the gas is proportional to the reciprocal of its absolute temperature $\dfrac{1}{T}$ if both $n$ and $T$ stays constant. In other words,

$V_2 = V_1 \cdot\dfrac{\dfrac{1}{P_2}}{\dfrac{1}{P_1}} = V_1\cdot\dfrac{P_1}{P_2} = 4.72122\times 10^{4}\;\text{L}\times\dfrac{0.995\;\text{atm}}{0.720\;\text{atm}}=6.52\times 10^{4}\;\text{L}$

(3 sig. fig. as in the question.).

See if you get the same result if you hold $T$ constant, change $P$ , and then move on to change $T$ .

6 0

3 years ago

HELP ASAP

Ket [755]

Answer:

Explanation:

statinary front is when a cold air mass and a warm air mass but are at a standstill the boundry is called statinary front sorry i could not give you other anwsers

8 0

2 years ago

The time required for one-half of the atoms from a sample of a radioactive substance to decay is called its _____.

Leya [2.2K]

The half life, this is how long it takes for half of the atoms to decay

6 0

3 years ago

A. 1.0 liter of a 1.0 M mercury (II) chloride (HgCl2) solution<br> IMO)

insens350 [35]

What mass of the following chemicals is needed to make the solutions indicated?

Answer:

271.6g

Explanation:

The mass of the chemicals need to make the needed solution can be derived by obtaining the number of moles first.

Given parameters:

Volume of solution = 1L

Molarity of HgCl₂ = 1M

number of moles of HgCl₂ = molarity of solution x volume

= 1 x 1

= 1 mole

From;

Mass of a substance = number of moles x molar mass;

we can find mass;

Molar mass of HgCl₂ = 200.6 + 2(35.5) = 271.6g/mol

Mass of the substance = 1 x 271.6 = 271.6g

4 0

3 years ago