What is the mass of 3.2 moles of Sulfur?
1 answer:
Answer:
820.864 g
Explanation:
1) The atomic mass of sulfur (found from the periodic table) is 32.065 amu. Use this mass to find the molar mass of Sulfur. Sulfur is S8 so the molar mass of sulfur is:
8 × 32.065 = 256.52 g/mol
2) To find the mass use the formula:
m = n × M where <em>m</em><em> </em>is the mass, <em>n</em><em> </em>is the number of moles, and <em>M</em><em> </em>is the molar mass.
3)
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Answer:
the mass of CaO present at equilibrium is, 0.01652g
Explanation:
= 3.8×10⁻²
Now we have to calculate the moles of CO₂
Using ideal gas equation,
PV =nRT
P = pressure of gas = 3.8×10⁻²
T = temperature of gas = 1000 K
V = volume of gas = 0.638 L
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mole.k
Now we have to calculate the mass of CaO
mass = 2.95 * 10 ⁻⁴ × 56
= 0.01652g
Therefore,
the mass of CaO present at equilibrium is, 0.01652g