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kati45 [8]
3 years ago
12

2 m3 of an ideal gas are compressed from 100 kPa to 200 kPa. As a result of the process, the internal energy of the gas increase

s by 10 kJ, and 150 kJ of heat is transferred to the surroundings. How much work was done by the gas during the process?
Physics
1 answer:
rosijanka [135]3 years ago
3 0

Answer:

work done is -150 kJ

Explanation:

given data

volume v1 = 2 m³

pressure p1 = 100 kPa

pressure p2 = 200 kPa

internal energy = 10 kJ

heat is transferred  = 150 kJ

solution

we know from 1st law of thermodynamic is

Q = du +W    ............1

put here value and we get

-140 = 10 + W

W = -150 kJ

as here work done is -ve so we can say work is being done on system

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A basketball of mass 0.608 kg is dropped from rest from a height of 1.37 m. It rebounds to a height of 0.626 m.
kenny6666 [7]

Answer:

a)|\Delta E|=4.58\: J  

b)F=61.90\: N

Explanation:

a)

We can use conservation of energy between these heights.

\Delta E=mgh_{2}-mgh_{1}=mg(h_{2}-h_{1})  

\Delta E=0.608*9.81(0.6026-1.37)

Therefore, the lost energy is:

|\Delta E|=4.58\: J  

b)

The force acting along the distance create a work, these work is equal to the potential energy.

W=\Delta E

F*d=mgh

Let's solve it for F.

F=\frac{mgh}{d}

F=\frac{0.608*9.81*1.37}{0.132}

Therefore, the force is:

F=61.90\: N

I hope is helps you!

6 0
2 years ago
A ray of light travels from a glass-to-liquid interface at an angle of 35.0º. Indices of refraction for the glass and liquid are
UkoKoshka [18]

Answer:

The angle of refraction for the ray moving through the liquid is = 32.3°

Explanation:

Refractive index of liquid (n₁/n₂) = sini/sinr

∴                 n₁/n₂ = sini/sinr ................ equation 1

n₁ = index of refraction for glass, n₂ = index of refraction for liquid

Where i = incident angle of the first medium, r = angle of refraction or angle in the second medium.

Since the light ray is traveling from glass - to - liquid,  the first medium is glass and the second medium is liquid. and the refractive index will be that liquid with respect to glass.

using the equation,

n₁/n₂ = sini/sinr

i = 35° , n₁ = 1.52, n₂= 1.63

Making sinr the subject of the equation above,

sinr = sini/(n₁/n₂)

sinr = sin35(1.52)/1.63

sinr =0.574(1.52)/1.63

sinr = 0.535

Taking the sin inverse of both side of the equation

sin⁻¹(sinr) = sin⁻¹(0.535)

∴ r = 32.3°

The angle of refraction for the ray moving through the liquid is = 32.3°

The right option is (b). 32.3°

5 0
3 years ago
Explain the difference between a conductor and an insulator. Give two examples of each.
docker41 [41]
There are different kinds of conductors, most notably electrical and thermal conductors. But they are often inclusive of each other (electrical conductors are typically good thermal conductors). A conductor transmits something through its body with high efficiency while an insulator does not transmit very well. In the case of electricity, a conductor transmits electrical energy between two points while an insulator blocks the flow of electricity. Two examples of conductors are copper and silver. Two examples of insulators are wood and styrofoam.
3 0
3 years ago
What are the units for electric current
Anettt [7]

Answer:

B) Amps

Which are called Ampere or Amp.

Explanation:

3 0
3 years ago
Find the acceleration of the blocks when the system is released. The coefficient of kinetic friction is 0.4, and the mass of eac
grin007 [14]

Answer:

a = 4.9(1 - sinθ - 0.4cosθ)

Explanation:

Really not possible without a complete setup.

I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g

                                     F = ma

mg - mgsinθ - μmgcosθ = (m + m)a

      mg(1 - sinθ - μcosθ) = 2ma

      ½g(1 - sinθ - μcosθ) = a

maximum acceleration is about 2.94 m/s² when θ = 0

acceleration will be zero when θ is greater than about 46.4°

8 0
3 years ago
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