A car of m = 1200. kg collides with a tree while traveling 60.0 mph. The collision occurs over a time period of 0.0500 seconds.
2 answers:
Answer:
Force, F = 38.4 N
Explanation:
It is given that,
Mass of the car, m = 1200 kg
Initial velocity of the car, u = 60 m/h = 0.016 m/s
The collision occurs over a time period of 0.0500 seconds.
Force, F = m a
F = -38.4 N
The magnitude of the force exerted on the car as it comes to rest during the collision is 38.4 N
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Answer:
(a) v = 5.42m/s
(b) vo = 4.64m/s
(c) a = 2874.28m/s^2
(d) Δy = 5.11*10^-3m
Explanation:
(a) The velocity of the ball before it hits the floor is given by:
(1)
g: gravitational acceleration = 9.8m/s^2
h: height where the ball falls down = 1.50m
The speed of the ball is 5.42m/s
(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.
You use the following formula:
(2)
vo: velocity of the ball where it starts its motion upward
You solve for vo and replace the values of the parameters:
The velocity of the ball is 4.64m/s
(c) The acceleration is given by:
The acceleration of the ball is 2874.28/s^2
(d) The compression of the ball is:
THe compression of the ball when it strikes the floor is 5.11*10^-3m
The initial velocity is 0.65 m/s
Explanation:
The motion of the roller coaster is a uniformly accelerated motion, so we can solve the problem by using the following suvat equation:
where
s is the displacement
u is the initial velocity
v is the final velocity
t is the time
For the roller coaster in this problem:
v = 35 m/s
t = 2.3 s
s = 41 m
Solving the equation for u, we find the initial velocity:
Learn more about accelerated motion:
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