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PilotLPTM [1.2K]
3 years ago
14

A buffer is a solution that is a mixture of either a weak acid and its conjugate base or a weak base and its conjugate acid. Whe

n strong acids or strong bases are added, buffers either accept protons when they are in excess or donate protons when they have been depleted to minimize changes in pH. Which of the statements correctly describe the properties of a buffer? Select one or more: a. The conjugate acid of an alkaline buffer will accept hydrogen protons when a strong base is added to the solution. b. The weak base of an alkaline buffer will accept hydrogen protons when a strong acid is added to the solution. c. The weak base of an alkaline buffer will donate hydrogen protons when a strong acid is added to the solution. d. The conjugate acid of an alkaline buffer will donate hydrogen protons when a strong base is added to the solution. e. An alkaline buffer solution is a mixture of a weak base and its conjugate acid. f. An alkaline buffer solution is a mixture of a weak acid and its conjugate base.
Chemistry
1 answer:
babymother [125]3 years ago
6 0

Answer:

b. The weak base of an alkaline buffer will accept hydrogen protons when a strong acid is added to the solution

d.The conjugate acid of an alkaline buffer will donate hydrogen protons when a strong base is added to the solution.

Explanation:

A buffer is a solution that resist pH change, it shows minimal change upon addition of small amount of strong acid or strong base. An alkaline buffer will have a  basic pH, above 7. It is made by mixing a weak base and its salt with a strong acid. An example of an alkaline buffer is carbonate-bicarbonate buffer that is prepared using varying amount of anhydrous sodium carbonate and volume of solution of sodium bicarbonate to get pH range between 9.2 to 10.7

Within the buffer,the salt is completely ionized while the weak base is partly ionized. on addition of acid, the released protons will be removed by the bicarbonate ion to form sodium carbonate; on addition of base, the hydroxide ion released by the base will be removed by the hydrogen ions to form water and the pH remains relatively the same

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How many liters of chlorine gas at 25°C and 0.950 atm can be produced by the reaction of 12.0 g of MnO2 with excess HCl(aq) acco
iragen [17]

Answer:

3.55 L.

Explanation:

We'll begin by calculating the number of mole in 12 g of MnO2. This can be obtained as follow:

Molar mass of MnO2 = 55 + (16×2)

= 55 + 32

= 87 g/mol

Mass of MnO2 = 12 g

Mole of MnO2 =...?

Mole = mass /Molar mass

Mole of MnO2 = 12 / 87

Mole of MnO2 = 0.138 mole

Next, we shall determine the number of mole Cl2 produced from the reaction. This is illustrated below:

The balanced equation for the reaction is given below:

MnO2(s) + 4HCl(aq) → MnCl2(aq) + 2H2O(l) + Cl2(g)

From the balanced equation above,

1 mole of MnO2 reacted to produce 1 mole of Cl2.

Therefore, 0.138 mole of MnO2 will also produce 0.138 mole of Cl2.

Finally, we shall determine the volume of Cl2 gas obtained from the reaction. This can be obtained as shown below:

Temperature (T) = 25 °C = 25 °C + 273 = 298 K

Pressure (P) = 0.950 atm

Number of mole (n) = 0.138 mole

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =.?

PV = nRT

0.950 × V = 0.138 × 0.0821 × 298

Divide both side by 0.950

V = (0.138 × 0.0821 × 298) / 0.950

V = 3.55 L

Therefore, 3.55 L of chlorine gas were obtained from reaction.

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3 years ago
An engineer is trying to create a fast reaction in a fuel mixture. Which should she do? A. Decrease the amount of fuel B. Lower
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To increase the rate of a reaction, you can either do any of the following:
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From these, the engineer should therefore do C. Adding a catalyst speeds up the reaction without really joining the reaction.
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Nimfa-mama [501]

Answer:

Its B

Explanation:

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3 years ago
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Steroids, which all share the same carbon-ring framework but differ in functional groups that are attached to the basic ring str
lawyer [7]

Answer:

Lipids.

Explanation:

Steroids are known as the type of lipid which consists of 4 rings of carbon atoms. All steroids have 1 five-sided carbon ring and a 3 six-sided carbon ring. They are works as a hormone in the body and secreted by the ovaries and testes.

Steroids differ in functional groups. When this functional group attached to the steroid ring it gives steroids with a different function. They are composed of largely carbon, and hydrogen atoms. They are insoluble in nature in water.

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3 years ago
A water treatment plant has 4 settling tanks that operate in parallel (the flow gets split into 4 equal flow streams), and each
ale4655 [162]

Answer:

a) When the 4 tanks operate in parallel the retention time is 1.26 hours.  

b) If the tanks are in series, the retention time would be 0.31 hours

Explanation:

The plant has 4 tanks, each tank has a volume V = 600 m_3. The total flow to the plant is Ft = 12 MGD (Millions of gallons per day)

When we use the tanks in parallel, it means that the total flow will be divided in the total number of tanks. F1 will be the flow of each tank.

Firstly, we should convert the MGD to m_3 /day. In that sense, we can calculate the retention time using the tank volume in m_3.

Ft =12 \frac{MG}{day}  (\frac{1*10^6 gall}{1MG} ) (\frac{3.78 L}{1 gall} ) (\frac{1 dm^3}{1L} ) (\frac{1 m^3}{10^3 dm^3} ) = 45360 \frac{m^3}{day}

After that, we should divide the total flow by four, because we have four tanks.

F1 = Ft/4 =(45360 \frac{m^3}{d} )/4 = 11 340 \frac{m^3}{d}

To calculate the retention time we divide the total volume V by the flow of each tank F1.

t1 =\frac{V1}{F1} = \frac{600 m^3}{11340  \frac{m^3}{d} }  = 0.0529 day\\t1 = 0.0529 d (\frac{24 h}{1d} ) = 1.26 h

After converting t1 to hours we found that the retention time when the four reactors are in parallel is 1.26 hours.

b)

If the four reactors were working in series, the entire flow goes first through one tank, then the second and so on. It means the total flow will be the flow of each tank.

In that order of ideas, the flow for reactors in series will be F2, and will have the same value of F0.

F2 = F0

To calculate the retention time t2 we divide the total volume V by the flow of each tank F2.

t2 =\frac{V1}{F2} = \frac{600 m^3}{45360  \frac{m^3}{d} }  = 0.01 day\\t2 = 0.01  d (\frac{24 h}{1d} ) = 0.31 h

After converting t2 to hours we found that the retention time when the four reactors are in series is 0.31 hours.

5 0
3 years ago
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