Answer:
0.00665
0.006951
Step-by-step explanation:
If the first child is born with the affliction, there's a 0.05 probability that the second child will be born with the affliction. Which means there's a 0.95 probability that they won't.
The probability that the first child is born with the affliction but not the second is therefore:
P = 0.007 × 0.95
P = 0.00665
There's a 0.007 probability that the first child will be born with the affliction, which means there's a 0.993 probability that they won't. If the first child isn't born with the affliction, then the probability the second child will have it is 0.007.
So the probability that the first child is not born with the affliction and the second child is would be:
P = 0.993 × 0.007
P = 0.006951
The answer is 5 large, 25 medium, 70 small dogs.
x - the number of large dogs
y - the number of medium dogs
z - the number of small dogs
<span>There are 100 dogs at Pampered Paws Kennel:
</span>x + y + z = 100
<span>Each day, the dogs eat 100 lb of food. Large dogs eat 3 lb, medium dogs eat 2 lb, and small dogs eat 0.5 lb:
3x + 2y + 0.5z = 100
</span><span>There are five times as many medium dogs as large ones:
x = 5y
</span>x + y + z = 100
3x + 2y + 0.5z = 100
y = 5x
____
Substitute y in the first two equations:
x + 5y + z = 100
3x + 2*5x + 0.5z = 100
___
6x + z = 100
13x + 0.5z = 100
____
z = 100 - 6x
13x + 0.5z = 100
____
13x + 0.5(100 - 6x) = 100
13x + 50 - 3x = 100
13x - 3x = 100 - 50
10x = 50
x = 50/10 = 5
y = 5x = 5 * 5 = 25
x + y + z = 100
5 + 25 + z = 100
30 + z = 100
z = 100 - 30
z = 70
Answer:
18
Step-by-step explanation:
Answer:
X25
Step-by-step explanation:
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