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Aleksandr-060686 [28]
3 years ago
11

I NEED HELP ASAP Which option best shows X< -6

Mathematics
1 answer:
nexus9112 [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Given x < - 6

Since less than, then looking for an open circle at - 6 on the number line

If ≤ then closed circle at - 6

Also since less than - 6 we are looking for the arrow pointing to the left indicating values less than - 6 , arrow right indicates greater than - 6

The option is therefore A

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As a result of a cyclone, the price of bananas rose 85% to $9.99 per kg. How much did bananas cost before the cyclone?
Karo-lina-s [1.5K]
The original price was $8.49 :)
7 0
4 years ago
Solve the following equation for s P=b+2s
laiz [17]

Answer:

s=P-b/2

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P-b=2s

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3 0
3 years ago
List all x intercepts for y= -cos(1/2x + 1/5 pi) on the interval [-2/5pi,4pi]
Dahasolnce [82]
- cos ( 1/2 x + 1/5 π ) = 0 ( and because if cos α = 0, α= π/2 + k π, k ∈ Z )
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Answer:
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3 0
4 years ago
Read 2 more answers
A parabola can be drawn given a focus of (-11, -2) and a directrix of x= -3
fgiga [73]

Check the picture below, so the parabola looks more or less like that.

now, the vertex is half-way between the focus point and the directrix, so that puts it where you see it in the picture, and the horizontal parabola is opening to the left-hand-side, meaning that the distance "P" is negative.

\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

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8 0
2 years ago
How to solve 3(2x-7)=5x+4
notka56 [123]
You have to start by using the distributive property on the left side.
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    +21      +21
6x=5x+25
-5x  -5x
x=25
3 0
4 years ago
Read 2 more answers
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