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Dahasolnce [82]

2 years ago

10

An advertisement claims a car can go from zero to 60 in 5 seconds. what is the rate of change of the car's speed?

1 answer:

Ugo [173]2 years ago

8 0

Rate of change=(changespeed)/(changetime)=(s1-s2)/(t1-t2)
change is (0-60)/(0-5)=-60/-6=12
answer is 12 units per second

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Which function represents exponential decay

mamaluj [8]

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4 0

3 years ago

If f(x)=4x^2 and g(x)=x+1, find (fog)(x)

iren [92.7K]

Answer: The value of $(f_\circ g)(x)$ is $4(x+1)^2$ .

Step-by-step explanation:

Given: $f(x) = 4x^2 \text { and } g(x) = x+1$

To find: $(f_\circ g)(x)$

As we know it is composition function which means that g(x) function is in f(x) function.

So we have

$(f_\circ g) (x) = f[g(x)]$

$\Rightarrow( f_\circ g)(x)= f(g(x)) = 4(g(x))^2$

Now substitute the value of g(x) we get

$(f_\circ g)(x)= 4(x+1)^2$

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3 years ago

A car uses a litre of petrol to travel 4km. How many litres will it use to travel 32 kilometres.

lesya [120]

Given that,

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2 years ago

If cot theta= 4/3, find csc theta

Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

$csc^2\theta=cot^2\theta+1$

Knowing that $cot\theta=\frac{4}{3}$ :

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$csc^2\theta=(\frac{4}{3})^2+1$

Simplify the expression:

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Solve for $csc\theta$ . Apply square root at both sides of the expression:

$\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}$

$csc\theta=\frac{5}{3}$

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maxonik [38]

Answer:

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Step-by-step explanation:

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