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e-lub [12.9K]
3 years ago
7

All the elements in group 1 react with water to form a hydroxide. What other substance is also

Chemistry
1 answer:
Iteru [2.4K]3 years ago
7 0
I’m not 100% sure, but I think hydrogen gas is also produced :)
You might be interested in
Which substance in an atom determines its chemical properties and allows elements to form chemical bonds?
Finger [1]
Electrons allow for chemical bonds to form.
7 0
4 years ago
Idk how to do this at all!!!
sergey [27]
Hello there!

I am not really sure which part you are talking about but let me answer some of them.

First, you need to read the information they gave you about glucose etc..

13- What is produced in photosynthesis?
"Photosynthesis is essential for all life on earth, because it provides food and oxygen."

Thus, the answer is: Photosynthesis produced food and oxygen.

14- What is the glucose used for?
"The glucose produced is used by the plant for energy and growth."

Thus, the answer is: The glucose used for energy and growth of the plants.

15- What is the oxygen used for?
"The oxygen produced is released into the air for us to breath."

Thus, the answer is: The oxygen used for us to breath.


I hope this helps!

Let me know if you have questions about the answer.

 
3 0
3 years ago
Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(
Semmy [17]

The balanced half-reaction for the product that forms at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻  

<h3>What is Balanced Chemical Equation ?</h3>

The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.

Now write the equation for FeI₂

At cathode:

Fe⁺² + 2e⁻ → Fe(s) Eo = - 0.44 V

2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V

It is easy to decrease Fe⁺² ions than the water, the product which is formed at cathode is Iron.

At anode:

2I⁻  → I₂ + 2e-    Eo = - 0.54 V

2H₂O  → O₂ + 4H⁺ + 4e⁻    Eo = -1.23 V

O₂ gas formed at anode.

Thus from the above conclusion we can say that The balanced half-reaction for the product at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

#SPJ4

6 0
2 years ago
Please help
Vika [28.1K]

Answer:

1 atom of carbon on the reactant side (CH₄ is methane, 1 carbon, 4 hydrogen).

1 atom of carbon on product side (Law of Conservation of energy proves this).

4 hydrogen on reactant side (CH₄ is methane, 1 carbon, 4 hydrogen).

4 hydrogen on product side (Again, the Law of Conservation of energy proves this)

4 oxygen atom on the reactant side (2O₂ means two diatomic molecules, or two oxygen molecules of 2 atoms each).

4 oxygen atoms on the product side (Law of Conservation of energy).

2 molecules of oxygen on the reactant side.

2 molecules of water on the product side

Yes, the chemical equation is balanced. The amount of atoms is the constant on both the reactant and product side.

A Ionic bond is chemical bond between two oppositely charged ions because of the transfer of valence electrons between them.

A covalent bond is a chemical bond in which two or more atoms share electrons between them. They can also form polar covalent bond or non-polar covalent bonds (Although that depends on the electronegativities of the atom).

The bond of a carbon dioxide molecule is covalent bond (Polar covalent bond if you've learned that yet)

Potassium Fluoride (KFl) form an ionic bond.

2Al₂O₃ --> 4Al + 3O₂

A reducing agent loses electrons while and oxidizing agent gains electrons.

In an endothermic reaction, the total bond energy in the reactants is greater than the bond energy of products so energy is absorbed by the reaction. (For an endothermic reaction, more energy needs to be absorbed than released).

8 0
3 years ago
what is the theoretical mass of xenon tetrafluoride that should form when 130.g of xenon is reacted with 100.g of F2? what is th
serg [7]

Answer:

The answer to your question is: 70.7 %

Explanation:

Equation

                  Xe   +   2F₂    ⇒    XeF₄

limiting reactant = Xe

Xe is the limiting reactant because the ratio is:

theoretical = 131/ 76 = 1.72 g

experimental ratio = 130/100 = 1.3  the amount of F increased.

                     131.3 g of Xe ------------------ 207 g of XeF₄

                     130 g of Xe  -------------------  x

                         x = (130 x 207) / 131.3

                        x = 205 g of XeF₄

% yield = 145 / 205 x 100

% yield = 70.7

5 0
3 years ago
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