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laiz [17]
3 years ago
13

The diagram above shows the repeating groups of atoms that make up two samples. Will the properties of the two samples likely be

the same or different? (Examples of properties are smell, color, and the temperature at which a substance melts.)

Chemistry
2 answers:
Fed [463]3 years ago
6 0
Completely off topic but I couldn’t help but notice you play valorant. If your down what’s ur name and tag line?
Ierofanga [76]3 years ago
6 0

Answer:

sorry i do not know

Explanation:

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Which of the following is not capable of reacting with molecular oxygen?
fredd [130]
I think letter b were you put the letters so
6 0
3 years ago
A beaker of water has a volume of 125mL and a density of 1.0g/mL. Calculate the mass of the water.​
Butoxors [25]

Answer:

125 g

Explanation:

D = m/v

1.0 g/mL = m /(125 mL)

125 g = m

6 0
3 years ago
Give the n and l values and the number of orbitals for sublevel 5g.
Pepsi [2]

The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

There are total four quantum numbers:

1) Principal quantum number , n

2) Angular quantum number , l

3) Magnetic quantum number , ml

4) spin quantum number , ms

For 5g shell, n = 5

subshell g , l = 4     ....0 - s , 1 - p , 2 - d, 3 - f, 4 -g

number of orbitals in subshell = (2l + 1)  ( 2×4 + 1) = 9

Thus,  The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

To learn more about quantum numbers here

brainly.com/question/14650894

#SPJ1

6 0
1 year ago
What is the ph of a solution of 0.400 m k2hpo4, potassium hydrogen phosphate?
dusya [7]
When we can get Pka for K2HPO4 =6.86 so we can determine the Ka :

when Pka = - ㏒ Ka

          6.86 = -㏒ Ka 

∴Ka = 1.38 x 10^-7

by using ICE table:

               H2PO4- →  H+  + HPO4
initial      0.4 m            0         0

change     -X                +X       +X

Equ       (0.4-X)               X          X

when Ka = [H+][HPO4] / [H2PO4-]

by substitution:

1.38 X 10^-7 = X^2 / (0.4-X)   by solving for X

∴X = 2.3x 10^-4 

∴[H+] = X = 2.3 x 10^-4

∴PH = -㏒[H+]

        = -㏒ (2.3 x 10^-4)
 ∴PH  =  3.6

3 0
3 years ago
The graph indicates the running route for Tobias.
Musya8 [376]

Answer: b

Explanation:

7 0
2 years ago
Read 2 more answers
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