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Alexus [3.1K]
3 years ago
10

Atoms can join together to form ______ substance​

Physics
1 answer:
ELEN [110]3 years ago
7 0

Answer:

Molecules

Explanation:

:)

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What is the total distance that the object traveled?
Natasha_Volkova [10]

Answer:

for what?

Explanation:

d=S x T

or

d=vt+1/2at2

srry if wrong but

hope this helps

take care

8 0
3 years ago
If 0.250 L of a gas weighs 0.308 g under normal conditions of pressure and temperature, what is its molecular weight?
Phantasy [73]

Answer:

=28

Explanation:

.25/22=0,11 mol

0.308/0,11=28

8 0
3 years ago
A solid 200-g block of lead and a solid 200-g block of copper are completely submerged in an aquarium filled with water. Each bl
finlep [7]

Answer:

B. The buoyant force on the copper block is greater than the buoyant force on the lead block.

Explanation:

Given;

mass of lead block, m₁ = 200 g = 0.2 kg

mass of copper block, m₂ = 200 g = 0.2 kg

density of water, ρ = 1 g/cm³

density of lead block, ρ₁ = 11.34 g/cm³

density of copper block, ρ₂ = 8.96 g/cm³

The buoyant force on each block is calculated as;

F_B = mg(\frac{density \ of \ fluid}{density \ of \ object} )

The buoyant force of lead block;

F_{lead} = 0.2*9.8(\frac{1}{11.34} )\\\\F_{lead} = 0.173  \ N

The buoyant force of copper block

F_{copper} = 0.2*9.8(\frac{1}{8.96})\\\\F_{copper} = 0.219  \ N

Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block

3 0
3 years ago
You have a grindstone (a disk) that is 90.0 kg, has a 0.340-m radius, and is turning at 90.0 rpm, and you press a steel axe agai
QveST [7]

Answer:

Explanation:

Given mass of grindstone m=90\ kg

radius of stone r=0.34\ m

angular speed of disc \omega =90\ rpm

Steel Axle applying a force of F=20\ N

coefficient of kinetic friction \mu =0.2

Frictional Torque applied by steel is given by

\tau=r\times f_r

\tau =r\times \mu F

where f_r=frictional force

\tau =r\times \mu \times F

\tau =0.34\times 0.2\times 20

\tau =1.36\ N-m

Torque is also given by

\tau =I\cdot \alpha

where \alpha=angular acceleration

I=moment of Inertia

\tau =0.5Mr^2\times \alpha

0.5Mr^2\times \alpha =1.36\ N-m

0.5\times 90\times 0.34^2\times \alpha =1.36

\alpha =0.261\ rad/s^2

3 0
3 years ago
POR FAVOR AYUDA !!!!!!!!!
lara [203]
Lololololololololololol
8 0
3 years ago
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