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raketka [301]
3 years ago
13

Two students, Student 1 and Student 2, did a hands-on mining exercise with cookies to compare the total cost of mining in two di

fferent land areas using different equipment. The table below shows the costs of land, equipment, mining, and reclamation for the two students.

Physics
1 answer:
grandymaker [24]3 years ago
3 0
Assume cost of equipment for student 2 is m.

We are given that:
Total mining cost for student 1 and student 2 is $40

For student 1:
We are given that:
Cost of land = $5
Cost of equipment = $2
Cost of mining and reclamation = $2 per minute
Time taken to mine = 5 minutes
Therefore,
Total mining cost for student 1= land + equipment
                                                  + cost of mining (time needed)
Total mining cost for student 1 = 2 + 5 + 2(5) = 7 + 10 = $17

This means that:
Total mining cost for student 2 = 40 - 17 = $23

For student 2:
We are given that:
Cost of land = $4
Cost of equipment = m
Cost of mining and reclamation = $2 per minute
Time taken to mine = 6 minutes
Total mining cost for student 2= $23
Therefore,
Total mining cost for student 2= land + equipment
                                                  + cost of mining (time needed)
23 = 4 + m + 2(6)
23 = 4 + m + 12
23 = 16 + m
m = 23 - 16
m = $7

Based on the above calculations, the correct choice would be:
c. $7
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The number of electrons emitted from the metal per second increases if the intensity of the incident light is increased.

Answer: Option B

<u>Explanation:</u>

As a result of photoelectric effect, electrons are emitted by the light incident on a metal surface. The emitted electrons count and its kinetic energy can measure as the function of light intensity and frequency. Like physicists, at the 20th century beginning, it should be expected that the light wave's energy (its intensity) will be transformed into the kinetic energy of emitted electrons.

In addition, the electrons count emitting from metal must vary with light wave frequency. This frequency relationship was expected because the electric field oscillates due to the light wave and the metal electrons react to different frequencies. In other words, the number of electrons emitted was expected to be frequency dependent and their kinetic energy should be dependent on the intensity (constant wavelength) of light.

Thus, the maximum in kinetic energy of electrons emitted increases with increase in light's frequency and is experimentally independent of light intensity. So, the number of emitted electrons is proportionate to the intensity of the incident light.

5 0
3 years ago
2. A person began running due east and covered 15 kilometers in 2.0 hours. What is the average velocity of the person?
Angelina_Jolie [31]

Answer:

7.5 km/h (2.1 m/s) due east

Explanation:

The average velocity of the person is given by:

v=\frac{d}{t}

where

d is the displacement

t is the time taken

In this problem,

d = 15 km is the displacement

t = 2.0 h is the time elapsed

so the average velocity is

v=\frac{15 km}{2.0 h}=7.5 km/h

and the direction is the same as the displacement (east).

We can also convert the velocity into SI units (m/s). We have:

d = 15 km = 15,000 m

t = 2.0 h * 3600 s/h = 7200 s

v=\frac{15,000 m}{7200 s}=2.1 m/s

4 0
3 years ago
Read 2 more answers
The cube with 2.00m wide and 2.00m long and 2.00m high has a weight of 960.00 N what pressure does it exert
andre [41]
2m X 2m = 4m ^2
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a u tube contains a liquid of an unknown density an oil of density is poured into the right arm of the tube until the oil column
scoray [572]

Answer:

The answer is "1155\ \frac{kg}{m^3}"

Explanation:

Please find the complete question in the attached file.

p = p_0 + ?gh

pi = pressure only at two liquids' devices

PA = pressure atmosphere.

1 = oil density

2 = uncertain fluid density

h_1 = 11 \ cm\\\\h_2= 3 \ cm

The pressures would be proportional to the quantity 11-3 = 8 cm from below the surface at the interface between both the oil and the liquid.

\to p_A + ?2g(h_1 - h_2) = p_A + ? 1gh_1\\\\\to ?2 = \frac{?1h_1}{(h_1 - h_2)} \\\\

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8 0
3 years ago
A 0.5 kg yellow bouncy ball rolls to the right at a speed of 8 m/s while a 0.25 kg blue bouncy ball rolls
inessss [21]

Explanation:

Let yellow ball be m1 = 0.5kg with u1 = 8 m/s and blue ball be m2 = 0.25 kg with u2 = - 4 m /s respectively.

After collision, blue ball travels 12 m/s.

<u>Using conservation of Linear Momentum</u> :

m1u1 + m2u2 = m1v1 + m2v2

0.5* 8 + 0.25 * - 4 = 0.5 * v1 + 0.25 * 12

v1 = 0 m/sec i.e. <u>Yellow ball comes to rest</u>.

3 0
3 years ago
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