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vaieri [72.5K]
3 years ago
13

Can negative intigers be turned into a fraction

Mathematics
2 answers:
Verdich [7]3 years ago
8 0
Yea Any integer can be written as a fraction! Just put that integer as the numerator of a fraction with a denominator
raketka [301]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

Any integer can be turned into a fraction.

For example, you have -2, to turn this integer into a fraction all you have to do is place -2 as a numerator and 1 as the denominator:

-2 = \frac{-2}{1} = -\frac{2}{1}

You can also change both values of the numerator and the denominator by multiplying the whole fraction by 2 only (to maintain the same value of -2):

-\frac{2 * 2}{1 * 2}  = -\frac{4}{2} which means -2 = -\frac{4}{2} = -\frac{8}{4} = -\frac{16}{8}  ...and the pattern goes on.

Matter of fact, this method works with any integer not only the negatives.

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Winslow buys 1.2 pounds of bananas. The bananas cost $1.29 per pound. To the nearest cent, how much does Winslow pay for the ban
NNADVOKAT [17]
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6) Mrs. Larson from Bay County Schools is in charge of buying supplies. She purchased 95
svp [43]

Answer:

$3708.80

Step-by-step explanation:

Since she bought 95 pencil sharpeners for $39.04, multiply 95 and 39.04.

95 × 39.04 = 3708.8

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3 years ago
A system of equations is graphed on the coordinate plane. y=−6x−3y=−x+2 What is the solution to the system of equations? Enter t
Mamont248 [21]
If you equate both, the y is eliminated:

-6x-3 = -x+2

Simplify this to find x:

-5x = 5
x = -1

Fill in x=-1 in either equation:

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3 years ago
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Pls if anyone knows the answer with work included/steps that will be greatly appreciated :)
dimaraw [331]

Answer:

1. Option D. 15x²

2. Option C. 3

Step-by-step explanation:

1. Determination of the area of one section.

Length (L) of one section = 25x/5 = 5x

Width (W) of one section = 3x

Area (A) of one section =?

The area of one section can be obtained as follow:

Area (A) = Length (L) × Width (W)

A = L × W

A = 5x * 3x

A = 15x²

Thus, the area of one section is 15x²

2. Determination of the expressions that are equivalent to (p²)³.

We'll begin by simplifying (p²)³. This can be obtained as follow:

(p²)³ = p²*³

(p²)³ = p⁶

Next we shall compare each expression given in the question above to see which will be the same as p⁶.

p × p × p × p × p × p = p¹⁺¹⁺¹⁺¹⁺¹⁺¹

p × p × p × p × p × p = p⁶

p² × p² × p² = p²⁺²⁺²

p² × p² × p² = p⁶

p² × p³ = p²⁺³

p² × p³ = p⁵

Thus,

p² × p³ ≠ p⁶

p⁵ ≠ p⁶

p⁶ = p⁶

SUMMARY

p × p × p × p × p × p = p⁶ = (p²)³

p² × p² × p² = p⁶ = (p²)³

p⁶ = (p²)³

Therefore, 3 expressions are equivalent to (p²)³. Option C gives the correct answer to the question.

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2 years ago
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lora16 [44]

Answer:

Step-by-step explanation:

Sorry I am not sure and don’t want to give you the wrong answer sorry again

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