Answer:
152.4 g of O₂ are consumed.
Explanation:
We start from the combustion reaction:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We convert the mass of propane to moles:
41.9 g . 1mol /44g = 0.952 moles
Ratio is 1:5. 1 mol of propane consumes 5 moles of oxygen at propane combustion
Then, 0.952 moles may consume (0.952 . 5) /1 = 4.76 moles.
We convert moles to mass → 4.76 mol . 32g/mol = 152.4 g
Answer:
yes; and because of how roughly they are played.
Explanation:
Answer:
3.99998575239 pounds per gallon (US)
To find the empirical formula you would first need to find the moles of each element:
58.8g/ 12.0g = 4.9 mol C
9.9g/ 1.0g = 9.9 mol H
31.4g/ 16.0g = 1.96 O
Then you divide by the smallest number of moles of each:
4.9/1.96 = 2.5
9.9/1.96 = 6
1.96/1.96 = 1
Since there is 2.5, you find the least number that makes each moles a whole number which is 2.
So the empirical formula is C5H12O2.