In this photograph what rock formation is presented by the blue lines?
2 answers:
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Use the following equations to fill the chart.
E = hf
where
h = 6.63 x 10⁻³⁴ J/s, Planck's constant
f = frequency Hz
E = quanta of energy, J
c = fλ
where
c = 3 x 10⁸ m/s, the velocity of light
λ = wavelength, m
If energy is given in J/mmol, divide by Avogadro's number, N = 6.02 x 10²³, to convert it to J.
The completed table is shown below.
E = hf
where
h = 6.63 x 10⁻³⁴ J/s, Planck's constant
f = frequency Hz
E = quanta of energy, J
c = fλ
where
c = 3 x 10⁸ m/s, the velocity of light
λ = wavelength, m
If energy is given in J/mmol, divide by Avogadro's number, N = 6.02 x 10²³, to convert it to J.
The completed table is shown below.
Answer:
Pentacarbon heptasilicide.
Explanation:
In order to name the following compound, we need to identify whether it is molecular or ionic.
Molecular compounds consist of non-metal atoms, while ionic compounds would have metal cations in their composition.
In the given compound, , we have two non-metals, carbon and silicon, meaning we should follow the molecular compound naming rules. The rules involve using prefixes to state the number of individual atoms.
The two prefixes required here are 'penta' for 'five' to indicate 5 carbon atoms present and 'hepta' for 'seven' to indicate 7 silicon atoms present.
The first part of the name would be pentacarbon (notice that the standard name for the first element is used). The second part would be heptasilicide (notice that the second atom would have an ending of -ide followed by the standard beginning of silicon).