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suter [353]
2 years ago
13

How many milliliters of a 0.1000 M NaOH solution would be needed to neutralize a 1.0000-g sample of potassium hydrogen phthalate

(KHC8H4O4) to a phenolphthalein endpoint, according to the following balanced equation?
KHC8H4O4(s)+NaOH(aq)------> KNaC8H4O4(aq)+H2O(l)
Chemistry
1 answer:
7nadin3 [17]2 years ago
7 0

Answer: 2) 2HCl(sq) + CaCO3(s) CaCl2(sq) + CO2(g) + H2O (l) No of moles of CaCO3 = amount of the CaCO3 (g)/mw of CaCO3 (g/mole)= 0.8085 g/100 g/mole = 0.008085

Explanation:

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Which is an example of an exothermic process? boiling of milk melting of wax freezing of water evaporation of water heating of w
Irina18 [472]

A.) Boiling of milk produces heat on the outside which is exothermic

8 0
4 years ago
Read 2 more answers
Select the structure that corresponds
Lostsunrise [7]

Answer:

C. both

Explanation:

8 0
2 years ago
What is the value for AG at 100 K if AH = 27 kJ/mol and AS = 0.09 kJ/mol.K)?
Aleonysh [2.5K]

The value for ΔG = 18 kJ/mol

<h3>Further explanation</h3>

Given

ΔH = 27 kJ/mol and ΔS = 0.09 kJ/mol.K

T = 100 K

Required

the value for ΔG

Solution

The spontaneous process of a reaction is based on 2 factors :

  • enthalpy change ΔH decreases and
  • entropy change ΔS increases

ΔG=ΔH-T.ΔS

\tt \Delta G=27~kJ/mol-100\times 0.09~kJ/mol.K\\\\\Delta G=18~kJ/mol

5 0
3 years ago
Draw the structure of two alkenes that would yield 1-methylcyclohexanol when treated with Hg(OAc)2 in water, then NaBH4:Draw the
disa [49]

Answer:

Two possible compounds are shown below- one with an exocyclic double bond and another one with an endocyclic double bond

Explanation:

Reaction of alkene with Hg(OAc)_{2} gives a complex of mercurous ion.

Then water molecule attacks this complex through S_{N}2 type reaction at more substituted position.

NaBH_{4} cleaves the resultant C-Hg bond and forms a C-H bond.

Two possible structures of an alkene is possible to yield 1-methylcyclohexanol which are shown below.

3 0
3 years ago
HELP!! BRAINLIEST 50 POINTS
zhenek [66]

Answer:

The given equation obey the law of conservation of mass.

Explanation:

Chemical equation:

2LiOH + CO₂  →   Li₂CO₃ + H₂O

There are equal number of atoms of oxygen, hydrogen and lithium on both side of equation so it obey the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

2LiOH                +            CO₂         →         Li₂CO₃           +                    H₂O

2(6.941 + 16 + 1)  +          12+32                   6.941×2 + 12 + 3×16     +       18

47.882 + 44                                                  13.882 +12+48   +   18

91.882 g                                                                91.882 g

The mass of reactants and product are equal.

6 0
3 years ago
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