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suter [353]
2 years ago
13

How many milliliters of a 0.1000 M NaOH solution would be needed to neutralize a 1.0000-g sample of potassium hydrogen phthalate

(KHC8H4O4) to a phenolphthalein endpoint, according to the following balanced equation?
KHC8H4O4(s)+NaOH(aq)------> KNaC8H4O4(aq)+H2O(l)
Chemistry
1 answer:
7nadin3 [17]2 years ago
7 0

Answer: 2) 2HCl(sq) + CaCO3(s) CaCl2(sq) + CO2(g) + H2O (l) No of moles of CaCO3 = amount of the CaCO3 (g)/mw of CaCO3 (g/mole)= 0.8085 g/100 g/mole = 0.008085

Explanation:

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What did GEM Anscombe stand for give a brief description?
KATRIN_1 [288]

Answer:

Explanation:

Anscombe is a philosopher who has approached contemporary themes, today enormously current, precisely in the ethical and social field, stimulating the development of virtue ethics as an alternative to utilitarianism, Kantian ethics and social contract theories. Anscombe argues that what we understand as a moral obligation, what we "must" do, is an obligation to God.

6 0
3 years ago
27. A solution has a pH of2. Which best describes the solution? (a point)
lianna [129]

Explanation:

solution has a pH of 2 is a strong acid.

5 0
3 years ago
Read 2 more answers
Balance this equation. Not all spots have to have a number.
Lisa [10]

2Na+2H2O----2NaOH+H2

3 0
3 years ago
a 125 g chunk of aluminum at 182 degrees Celsius was added to a bucket filled with 365 g of water at 22.0 degrees Celsius. Ignor
Diano4ka-milaya [45]
<h3>Answer:</h3>

32.98°C

<h3>Explanation:</h3>

We are given the following;

Mass of Aluminium as 125 g

Initial temperature of Aluminium as 182°C

Mass of water as 265 g

Initial temperature of water as 22°C

We are required to calculate the final temperature of the two compounds;

First, we need to know the specific heat capacity of each;

Specific heat capacity of Aluminium is 0.9 J/g°C

Specific heat capacity of water is 4.184 J/g°C

<h3>Step 1: Calculate the Quantity of heat gained by water.</h3>

Assuming the final temperature is X°C

we know, Q = mcΔT

Change in temperature, ΔT = (X-22)°C

therefore;

Q = 365 g × 4.184 J/g°C × (X-22)°C

    = (1527.16X-33,597.52) Joules

<h3>Step 2: Calculate the quantity of heat released by Aluminium </h3>

Using the final temperature, X°C

Change in temperature, ΔT = -(X°- 182°)C (negative because heat was lost)

Therefore;

Q = 125 g × 0.90 J/g°C × (182°-X°)C

  = (20,475- 112.5X) Joules

<h3>Step 3: Calculating the final temperature</h3>

We need to know that the heat released by aluminium is equal to heat absorbed by water.

Therefore;

(20,475- 112.5X) Joules = (1527.16X-33,597.52) Joules

Combining the like terms;

1639.66X = 54072.52

             X = 32.978°C

                = 32.98°C

Therefore, the final temperature of the two compounds will be 32.98°C

7 0
3 years ago
A swimming-pool worker wants the pool's pH to be 7.2. She comes by to test the water and finds that the pH is 6.2. What should s
vichka [17]
The swimming pools pH is below 7, meaning it is slightly acidic. If you want to make the pH higher, you must add a base which by definition has a pH higher than 7.

D. Add base
5 0
3 years ago
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