1. What is the acceleration in m/s^2 of a car that slows from 50mi/hr to 25 mi/hr in 5 minutes?
1 answer:
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Answer: Decreasing the distance of the space shuttle from Earth .
Explanation:
According to expression of gravitational force:
G = gravitational constant
= masses of two objects
r = Distance between the two objects.
F = Gravitational force
From the above expression we can say that gravitational force is inversely proportional to squared of the distance between the two masses.
So, in order to increase the gravitational force on space shuttle distance between the space space shuttle must be decreased.
Hence, the correct answer 'decreasing the distance of the space shuttle from Earth '.
Answer:
speed of electrons = 3.25 × m/s
acceleration in term g is 3.9 × g.
radius of circular orbit is 2.76 × m
Explanation:
given data
voltage = 3 kV
magnetic field = 0.66 T
solution
law of conservation of energy
PE = KE
qV = 0.5 × m × v²
v =
v =
v = 3.25 × m/s
and
magnetic force on particle movie in magnetic field
F = Bqv
ma = Bqv
a =
a =
a = 3.82 × m/s²
and acceleration in term g
a =
a = 3.9 × g
acceleration in term g is 3.9 × g.
and
electron moving in circular orbit has centripetal force
F =
Bqv =
r =
r =
r = 2.76 × m
radius of circular orbit is 2.76 × m