the electric conductivity of gold is very high
Answer:
accelerating
Explanation:
If we consider(v > u) Acceleration:
final velocity(v)= 14m/s
initial velocity(u)=10m/s
time taken(t)= 2 seconds
a=
=2m/s²
If we consider (v<u) Deceleration:
final velocity(v)= 3m/s
initial velocity(u)=9m/s
time taken(t)=2 seconds
a=
= -3m/s²
Answer:
Approximate atomic radius for polonium-209 is 167.5 pm .
Explanation:
Number of atom in simple cubic unit cell = Z = 1
Density of platinum = 
Edge length of cubic unit cell= a = ?
Atomic mass of Po (M) = 209 g/mol
Formula used :

where,
ρ = density
Z = number of atom in unit cell
M = atomic mass
= Avogadro's number
a = edge length of unit cell
On substituting all the given values , we will get the value of 'a'.


Atomic radius of the polonium in unit cell = r
r = 0.5a



Approximate atomic radius for polonium-209 is 167.5 pm.
Answer:
4400 Joules
73.33 Joules
25.9325 Joules
Explanation:
P = Power = 800 W
t = Time = 22 s
F = Force
r = Radius of arm = 90 cm
Energy

As the efficiency is 25%

Energy used in the race is 4400 Joules
Half of the energy is used in the arm

So, per stroke of paddle

The energy expenditure per arm stroke is 73.33 Joules
Displacement will be the half of the perimeter of the circle

Work done

The average force of the hand on the water is 25.9325 Joules
Answer:
The correct answer is V√5
Explanation:
Let V be the velocity of the satellite orbiting at radius r.
Let V(5r) be the velocity of the satellite orbiting at radius 5r.
Recall:
Escape velocity is given by:
V = √(2gr)
Where V is the escape velocity
g is the acceleration due to gravity
r is the radius of the earth.
With the above equation, we can obtain the answer to the question as follow:
V = √(2gr)
V(5r) = √(2g5r)
Next, we'll obtained the ratio of V(5r) to V as shown below
V(5r) : V => V(5r)/V
V(5r)/V = √(2g5r) / √(2gr)
V(5r)/V = √5
Cross multiply
V(5r) = V√5
From the above illustration, we can see that when the satellite is moved to 3r, then the expression for the velocity will be V√5