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choli [55]
2 years ago
12

HELP ME PLZ!!! Two lifeguards pull on ropes attached to a

Physics
1 answer:
yan [13]2 years ago
7 0

When both pull in the same direction, their net is 352.
When they pull in opposite directions, the net in one direction is 157.

If you want to set up the system of equations,
you should start with

                                   A + B  =  352
                                   A  - B  =  157 .

then add them, etc.

You'll find that

-- Guy-A is the stronger one. 
   He's the one who moves to the other side,
   and he pulls with  254.5 newtons both times.

-- Guy-B is the less strong one.
   He stays put, and pulls with 97.5 newtons.
 
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A skateboarder wants to cross a large playground and notices that there are large shapes painted on its asphalt surface. One sha
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<h2>Diagonal of circle </h2>

Explanation:

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We have formula:

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Te force applied cannot be changed , so he is to decrease the distance .

In case of circle , diameter is the minimum distance . Thus he is supposed to move along it .

6 0
3 years ago
A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves downstream at a velocity of 15 km/h relative to th
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3 years ago
The electron beam inside a television picture tube is 0.40 {\rm mm} in diameter and carries a current of 50 {\rm \mu A}. This el
Harrizon [31]

Answer:

A.3.13x10^14 electrons

B.330A/m²

C.9.11x10^5N/C

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.pls see attached file for explanations

8 0
3 years ago
Technician A says that the battery must be in good condition and at least 75% charged to accurately test an alternator. Technici
aalyn [17]

Answer:Technician A

Explanation:

Technician A statement is correct as  

The battery is required to start the vehicle which, in effect, rotates the alternator at sufficient speed to keep the battery charged. This means if the battery is low it is not possible to start the vehicle and thus we are unable to test the alternator.  

That is the battery is pre-requisite to test the alternator. So the battery must be at least a 75 % charge to test the alternator.

5 0
3 years ago
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
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Answer:

2.1406 ×10^6 m/sec

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we know that energy is always conserved

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qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

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so for electron

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so the velocity of electron will be 2.1406×10^6 m/sec

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